Area=54
l2=54
l =3√6
volume=(3√6)3
=396.81
Explanation:
A splint is lit and held near the opening of the tube, then the stopper is removed to expose the splint to the gas. If the gas is flammable, the mixture ignites. This test is most commonly used to identify hydrogen, which extinguishes with a distinctive 'squeaky pop' sound.
Answer:
Technicians A.
Explanation:
Since air compressor uses series of processes that turn incoming ambient air into a power source for tools and machinery. This means that air compressor has many different parts, and each of these parts must be maintained to ensure they function properly and optimally.
These are the basis when it comes to servicing a compressor
You need to change its oil
And clean its filters.
Inspected it's filters every three months, and have its filters replaced and connections tightened at least once every year.
To do all these can be performed on the vehicle if there is enough space just as Technician A said for the question context.
Answer:
138,516,546.9 horas.
Explanation:
Tenemos que usar la ecuación:
Velocidad = distancia/tiempo
Acá tenemos:
Velocidad = 0.3m/s
distancia = 149597870700 m
y queremos resolver la ecuación para el tiempo:
0.3m/s = 149597870700m/tiempo.
tiempo = 149597870700m/(0.3m/s) = 498,659,569,000 s
y sabemos que una hora tiene 3600 segundos, entonces si queremos transformar de segundos a horas tenemos:
498,659,569,000 s = (498,659,569,000/3600) h = 138,516,546.9 horas.
Answer:
<em>The velocity after the collision is 2.82 m/s</em>
Explanation:
<u>Law Of Conservation Of Linear Momentum
</u>
It states the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is
P=mv.
If we have a system of two bodies, then the total momentum is the sum of the individual momentums:
If a collision occurs and the velocities change to v', the final momentum is:
Since the total momentum is conserved, then:
P = P'
Or, equivalently:
If both masses stick together after the collision at a common speed v', then:
The common velocity after this situation is:
There is an m1=3.91 kg car moving at v1=5.7 m/s that collides with an m2=4 kg cart that was at rest v2=0.
After the collision, both cars stick together. Let's compute the common speed after that:
The velocity after the collision is 2.82 m/s
