I was thinking that the question would be to find for the operating temperature of the reaction. Change in entropy is equal to the total energy divided by the temperature. Assuming it is isothermal, internal energy would be zero. Therefore, the temperature would be:
T = 129000/301 = 428.57 K
A) 5.2 x 10^2
B) 86.
C) 6.4 x 10^3
D) 5.0
E) 22.
F) 0.89
Answer:
1. C(s) + O₂(g) ⇄ CO₂(g)
2. ![K=\frac{[CO_{2}]}{[O_{2}]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BCO_%7B2%7D%5D%7D%7B%5BO_%7B2%7D%5D%7D)
Explanation:
<em>When the oxide of generic metal M is heated at 25.0 °C, a negligible amount of M is produced. MO₂( s ) ⇄ M(s) + O₂(g) ΔG° = 290.2 kJ/mol.</em>
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<em>1. When this reaction is coupled to the conversion of graphite to carbon dioxide, it becomes spontaneous. What is the chemical equation of this coupled process? Show that the reaction is in equilibrium. Include physical states and represent graphite as C(s).</em>
The chemical equation for the coupled reaction is:
C(s) + O₂(g) ⇄ CO₂(g)
<em>2. What is the thermodynamic equilibrium constant for the coupled reaction?</em>
The thermodynamic equilibrium constant (K) is the product of the concentration of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to their stoichiometric coefficients. Only gases and aqueous species are included.
![K=\frac{[CO_{2}]}{[O_{2}]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BCO_%7B2%7D%5D%7D%7B%5BO_%7B2%7D%5D%7D)
It's true
There are thousands of combinations that can be put together to form a all sorts of compounds. That's the whole basis of inorganic chemistry. Organic chemistry is a little bit different. It is more restricted.