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gizmo_the_mogwai [7]
3 years ago
8

How might an ecologist Measure population density of pine trees in an actual forest?

Physics
1 answer:
ruslelena [56]3 years ago
4 0
<span>Ans : The best way to estimate the population density of pine trees in an actual forest is to count the number of trees in a small area and than multiply to find the number in a large area. To get the most accurate estimate, your sample area should be typical of the larger area. Suppose you count 10 pine tree in 100 sq meters of the forest. If the entire forest were 100 times the size, you would multiply your count by 100 to estimate the total population density, or 1000 (10X100) pine trees.</span>
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What best describes a sound wave? transverse and electromagnetic longitudinal and mechanical longitudinal and electromagnetic tr
GalinKa [24]

Sound needs medium to travel and it can not travel without medium

so sound wave is a travelling wave

now we also know that sound wave propagate in form of rarefaction and compression.

So all medium particles travel in the direction of wave only

so it is a longitudinal wave also

so correct answer will be

<em>mechanical longitudinal </em>

7 0
3 years ago
Read 2 more answers
An advantage of parallel circuits is that they A) stop transmitting all current if even one resistor breaks. B) form a single pa
svetoff [14.1K]

Parallel circuits allow current to flow even if some paths are cut, because a parallel circuit has more than one current-carrying path through it.

4 0
3 years ago
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Given that a lever has a mechanical advantage of 6.0 and is 100% efficient, if the resistance is to be lifted 2.0 inches, then h
Shalnov [3]
The mechanical advantage of a machine is the ratio of the force produced by the machine to the force applied to it. Therefore, we may calculate the applied force using:
Mechanical advantage = force by machine / force applied
6 = 2 / force applied
Force applied = 1/3

Thus, the distance that the effort must move will be 1/3 inch
5 0
3 years ago
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Estimate the constant rate of withdrawal (in m3 /s) from a 1375 ha reservoir in a month of 30 days during which the reservoir le
kap26 [50]

Answer:

Explanation:

1 ha = 10⁴ m²

1375 ha = 1375 x 10⁴ m² = 13.75 x 10⁶ m²

In flow in a month = .5 x 10⁶ x 30 m³ = 15 x 10⁶ m³

Net inflow after all loss = 18.5 - 9.5 - 2.5 cm = 6.5 cm = .065 m

Net inflow in volume = 13.75 x 10⁶ x .065 m³= .89375 x 10⁶ m³

Let Q be the withdrawal in m³

Q - 15 x 10⁶ - .89375 x 10⁶ = 13.75 x 10⁶ x .75 = 10.3125 x 10⁶

Q = 26.20 x 10⁶ m³

rate of withdrawal per second

= 26.20 x 10⁶ / 30 x 24 x 60 x 60

= 26.20 x 10⁶ / 2.592 x 10⁶

= 10.11 m³ / s

6 0
3 years ago
The electric field everywhere on the surface of a thin, spherical shell of radius 0.770 m is of magnitude 860 N/C and points rad
11111nata11111 [884]

Answer:

(a) Q = 7.28\times 10^{14}

(b) The charge inside the shell is placed at the center of the sphere and negatively charged.

Explanation:

Gauss’ Law can be used to determine the system.

\int{\vec{E}} \, d\vec{a} = \frac{Q_{enc}}{\epsilon_0}\\E4\pi r^2 = \frac{Q_{enc}}{\epsilon_0}\\(860)4\pi(0.77)^2 = \frac{Q_{enc}}{8.8\times 10^{-12}}\\Q_enc = 7.28\times 10^{14}

This is the net charge inside the sphere which causes the Electric field at the surface of the shell. Since the E-field is constant over the shell, then this charge is at the center and negatively charged because the E-field is radially inward.

The negative charge at the center attracts the same amount of positive charge at the surface of the shell.

5 0
3 years ago
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