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ANTONII [103]
3 years ago
13

Phyllis had always been the one to take care of Douglas, now he feels as if it is his duty and privilege to take care of her, ev

en though others don’t agree. Choose two positive critical thinking habits of mind and write one to three sentences for each habit to support how Douglas may have defended his position on being the primary care taker for his wife.
Physics
2 answers:
a_sh-v [17]3 years ago
7 0
1. Confident in Reasoning: Douglas is truthful of his reasoning skills to yield good judgments.

2. Analytical: <span>Douglas is habitually alert to potential problems and vigilant in anticipating consequences and trying to foresee short-term and long-term outcomes of being primary care taker for his wife. </span>
Ivan3 years ago
5 0

Use the method for making decision and describe how these steps apply to Douglas decision to take care of Phyllis. Gather all relevant information and evaluate the pros and cons of each possible choice. step 3

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Part A What will be the equilibrium temperature when a 227 g block of copper at 283 °C is placed in a 155 g aluminum calorimeter
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Answer:

T = 20.84°C

Explanation:

From the law of conservation of energy:

Heat Lost by Copper Block = Heat Gained by Aluminum Calorimeter + Heat Gained by Water

m_cC_c\Delta T_c = m_wC_w\Delta T_w + m_aC_a\Delta T_a

where,

m_c = mass of copper = 227 g

m_w = mass of water = 844 g

m_a = mass of aluminum = 155 g

C_c = specific heat capacity of calorimeter = 385 J/kg.°C

C_w = specific heat capacity of water = 4200 J/kg.°C

C_a = specific heat capacity of aluminum = 890 J/kg.°C

\Delta T_c = change in temperature of copper = 283°C - T

\Delta T_w = change in temperature of water = T - 14.6°C

\Delta T_a = change in temperature of aluminum = T - 14.6°C

T = equilibrium temperature = ?

Therefore,

(227\ g)(385\ J/kg.^oC)(283^oC-T)=(844\ g)(4200\ J/kg.^oC)(T-14.6^oC)+(155\ g)(890\ J/kg.^oC)(T-14.6^oC)\\\\24732785\ J - (87395\ J/^oC) T = (3544800\ J/^oC) T - 51754080\ J+ (137950\ J/^oC) T-2014070\ J\\\\24732785\ J +51754080\ J+2014070\ J = (3544800\ J/^oC) T+(137950\ J/^oC+(87395\ J/^oC) T\\\\78560935\ J = (3770145\ J/^oC) T\\\\T = \frac{78560935\ J}{3770145\ J/^oC}

<u>T = 20.84°C</u>

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