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ziro4ka [17]
3 years ago
14

What is the acceleration of a skydiver who starting from rest reaches a speed of 40m/s in 4s?

Physics
2 answers:
Colt1911 [192]3 years ago
5 0

Answer: 10 meters/ second squared

Explanation:

started from rest means that its initial velocity is 0

acceleration=(v final - v initial) / time

a= (40 - 0)/4

a= 10

cupoosta [38]3 years ago
5 0
The Acceleration is = 10m/s
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A group of protons and neutrons surrounded by electrons

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What is the most important safety rule in cycling?
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Wear a helmet. Stay visible; use bike lights and/or wear bright clothes. Look and Signal; use hand signals to let drivers know where you're going, try to make eye contact with them and look before you go.

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What can increase the gravitational potential energy of a object
love history [14]

Answer:

Increase in mass and height

Explanation:

The gravitational potential energy of an object can increase if the mass and height of object is increased.

Gravitational potential energy is the energy due to the position of a body.

It is expressed as:

  Gravitational potential energy = mass x acceleration due gravity x height

Increasing mass and height will cause an increase in gravitational potential energy.

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2 years ago
The highest occupiable floor of any building is in the Sears Tower in Chicago. The elevators of the central tower of the buildin
irina1246 [14]

Answer:

9727160J

Explanation:

Given parameters:

Height of elevator rise  = 436m

Force exerted  = 22310N

Unknown:

Work done by the elevator lifting mechanism = ?

Solution:

The work done by a body is the force applied to move a body in a specific direction;

          Work done  = force x distance moved

In this case, the force and distance moved is provided already;

        Work done  = 22310 x 436  = 9727160J

3 0
3 years ago
A small block with mass 0.0400 kg slides in a vertical circle of radius 0.600 m on the inside of a circular track. During one of
Maurinko [17]

Answer:

Explanation:

Given that

The mass of the body is 0.04kg

M=0.04kg

The radius of the paths is 0.6m

r=0.6m

The normal force exerted at A is 3.9N

Fa=3.9N

The normal force exerted at B is 0.69N

Fb=0.69N

Then work done by friction from point A to B will be the change in K.E

W=∆K.E+P.E

So we need to know the velocity at both point A and B

Then since the centripetal force is given as

Ft=mv²/r

Then,

For point A

Fa=mv²/r

3.9=0.04v²/0.6

3.9=0.0667v²

v²=3.9/0.0667

v²=58.5

v=√58.5

v=7.65m/s

Va=7.65m/s

Now at point B

Fb=mv²/r

0.69=0.04v²/0.6

0.69=0.0667v²

v²=0.69/0.0667

v²=10.35

v=√10.35

v=3.22m/s

Vb=3.22m/s

Then, the work done is

W=∆K.E+P.E

P.E is given as mgh

The height will be 2R =1.2m

P.E=mgh

P.E=0.04×9.81×1.2

P.E=0.471J

Final kinetic energy at B minus initial kinetic energy at A

W=K.Eb-K.Ea

K.E is given as 1/2mv²

W=1/2m(Vb²-Va²) +P.E

W=0.5×0.04(3.22²-7.65²) +0.471

W=0.5×0.04×(-48.1541) +0.471

W=-0.96+0.471

W=-0.49J

work was done on the block by friction during the motion of the block from point A to point B is 0.49J.

Friction opposes motions and that is why the work done is negative

3 0
3 years ago
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