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ziro4ka [17]
3 years ago
14

What is the acceleration of a skydiver who starting from rest reaches a speed of 40m/s in 4s?

Physics
2 answers:
Colt1911 [192]3 years ago
5 0

Answer: 10 meters/ second squared

Explanation:

started from rest means that its initial velocity is 0

acceleration=(v final - v initial) / time

a= (40 - 0)/4

a= 10

cupoosta [38]3 years ago
5 0
The Acceleration is = 10m/s
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A theory becomes obsolete or superseded if it becomes inadequate, false or incomplete in how its describes reality. It does not matter if it was once accepted. There are some theories such as Lysenkoism that are currently described as being obsolete because it does not conform to current reality. Another example of a theory that was superseded is the phlogiston theory. It was replaced a different theory of energy.

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A 1900kg car starts from rest and drives around a flat 65-m-diameter circular track. The forward force provided by the car's dri
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3 years ago
A 49 kg person is being dragged in their sleeping bag to the lake by a 593 N
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3 years ago
A 15x10^-6c charge is placed at the origin and a 9x10^-6C charge is placed on the x-axis at x=1.00m. where, on the x-axis is the
Harlamova29_29 [7]

The Electric field is zero at a distance 2.492 cm from the origin.

Let A be point where the charge 15\times10^-6 C is placed which is the origin.

Let B be the point where the charge 9\times 10^-6 C is placed. Given that B is at a distance 1 cm from the origin.

Both the charges are positive. But charge at origin is greater than that of B. So we can conclude that the point on the x-axis where the electric field = 0 is after B on x - axis.

i.e., at distance 'x' from B.

Using Coulomb's law, \frac{kQ_A^2}{d_A^2} = \frac{kQ_B^2}{d_B^2},

Q_A = 15\times 10^-6 C

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k is the Coulomb's law constant.

On substituting the values into the above equation, we get,

\frac{(15\times10^-6)^2}{(1+x)^2} =\frac{(9\times10^-6)^2}{x^2}

Taking square roots on both sides and simplifying and solving for x, we get,

1.67x = 1+x

Therefore, x = 1.492 cm

Hence the electric field is zero at a distance 1+1.492 = 2.492 cm from the origin.

Learn more about Electric fields and Coulomb's Law at brainly.com/question/506926

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