When firing straight up:
v^2 = u^2 - 2gh, where v = final velocity = 0, u = initial velocity, g = gravitational acceleration, h = maximum height attained.
Then,
0 = u^2 - 2gh
u = Sqrt (2gh) ---- (1)
When firing at 45°,
Initial velocity, U = u Sin 45 = Sqrt (2gh)·Sin 45
Maximum height, H = U^2*(Sin Ф)^2/2g
substituting;
H = [Sqrt (2gh)·Sin 45]^2*(Sin 45)^2]/2g
H = [2gh*(Sin 45)^2*(Sin 45)^2]/2g
H = [h*(Sin 45)^4] = h/4
Therefore, maximum height when the gun fires at 45° is a quarter of maximum height when the gun fires vertically up.
1. Volume
2. liquid
3. Gas
4. Kinetic energy?
5.Gas
I think to see further away
Answer: 6m/s²
Explanation:
Acceleration = change in velocity / time
Initial velocity = 4m/s
Final velocity = 22m/s
Time = 3s
Acceleration = (22 - 4) / 3
a = 18 / 3 = 6m/s²
These rocks can be any of the following listed but they cannot be solid aa lava. This is because solid aa lava would not be smooth, rounded rocks and would not be scattered on the ground.
