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Eva8 [605]
3 years ago
15

Write a net ionic equation for the following:

Chemistry
1 answer:
Ann [662]3 years ago
6 0

Explanation:

Al(OH)4-(aq) plus 4H plus (aq) and Al3 plus (aq) plus 4H20(I)

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What mass of sulfur has to burn to produce 4.5L SO2 at 300°C and 101 kPa in the following reaction?s(s)+O2(g) SO,(g)
Alex_Xolod [135]
<span>Answer: option B. 3.07 g

Explanation:

1) given reaction:

S(s) + O₂ (g) → SO(g)

2) Balanced chemical equation:

</span><span>2S(s) + O₂ (g) → 2SO(g)

3) Theoretical mole ratios:

2 mol S : 1 mol O₂ : 2 mol SO

3) number of moles of 4.5 liter SO₂ at</span><span> 300°C and 101 kPa

use the ideal gas equation:

pV = nRT

with V = 4.5 liter
p = 101 kPa
T = 300 + 273.15 K = 573.15 K
R = 8.314 liter×kPa / (mol×K)

=> n = pV / (RT) =

n =  [101 kPa × 4.5 liter] / [8.314 (liter×kPa) / (mol×K)  × 573.15 K ]

n = 0.0954 mol SO

4) proportion with the theoretical ratio S / SO

 2 mol S                   x
-------------- = ----------------------
 2 mol SO      0.0954 mol SO

=> x = 0.0954 mol S.

5) Convert mol of S to grams by using atomic mass of S = 32.065 g/mol

mass = number of moles × atomic mass

mass = 0.0954 mol × 32.065 g/mol = 3.059 g of S

6) Therefore the answer is the option B. 3.07 g
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4 years ago
What is an empirical formula for a compound that is 82.2% nitrogen and 17.8% hydrogen
makkiz [27]
Percent to mass
Mass to mole
Divide by small
Multiply 'til whole

Assume 100 g of substance, then 82.2 g N and 17.8 g H.

82.2 g N * (1 mol/14.01 g N) = 5.86 mol N
17.8 g H * (1 mol/1.01 g H) = 17.6 mol H

Divide by the smallest mole
17.6 H / 17.6  = 1 H
5.86 N / 17.6 =  1/3 N

Multiply to make whole number ( x3 in this case)
3 x 1 H = 3H
3 x 1/3 N = 1 N

NH3
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