Answer:
0.238 M
Explanation:
A 17.00 mL sample of the dilute solution was found to contain 0.220 M ClO₃⁻(aq). The concentration is an intensive property, so the concentration in the 52.00 mL is also 0.220 M ClO₃⁻(aq). We can find the initial concentration of ClO₃⁻ using the dilution rule.
C₁.V₁ = C₂.V₂
C₁ × 24.00 mL = 0.220 M × 52.00 mL
C₁ = 0.477 M
The concentration of Pb(ClO₃)₂ is:
Answer:
Final temperature of the gas is 576 .
Explanation:
As the amount of gas and pressure of the gas remains constant therefore in accordance with Charles's law:
where and
are volume of gas at
and
temperature (in kelvin scale) respectively.
Here ,
and
So
849 K = (849-273) = 576
So final temperature of the gas is 576 .