Question

What is the electron configuration for an electrically neutral atom of oxygen? Use the periodic table. 1s22s22p44d2 1s22s2 1s22s22p6 1s22s22p4

Answer 1

Answer:

O₈ = 1s² 2s² 2p⁴

Explanation:

An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.

All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example if neutral atom has 6 protons than it must have 6 electrons. The sum of neutrons and protons is the mass number of an atom while the number of protons are number of electrons is the atomic number of an atom.

Electronic configuration for electrically neutral oxygen atom.

O₈ = 1s² 2s² 2p⁴

oxygen has six valance electrons 2s² 2p⁴. To complete the octet oxygen needed two more electrons that's why in chemical bonding oxygen accept the electrons.