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vlabodo [156]
3 years ago
5

A teacher buys 50 train tickets for a school trip for a total cost of $1,200. She buys x number of student tickets for $20 each.

She also buys y number of adult tickets for $30 each. How many adult tickets did she buy?
Mathematics
1 answer:
Aleks04 [339]3 years ago
3 0

Answer:

y=20 , x =30

Step-by-step explanation:

x+y=50;  

20x+30y=1200

20x+20y=1000, multiplying the top by 20

-20x-30y=-1200, subtracting the second.

-10y=-200

y=20 adult tickets ($600)

x=30 student tickets ($600)

(add up to $1200)

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patriot [66]

Answer:

Choice b.

x^{2} + 5\, x + 6 = (x + 3)\, (x + 2).

Step-by-step explanation:

The highest power of the variable x in this polynomial is 2. In other words, this polynomial is quadratic.

It is thus possible to apply the quadratic formula to find the "roots" of this polynomial. (A root of a polynomial is a value of the variable that would set the polynomial to 0.)

After finding these roots, it would be possible to factorize this polynomial using the Factor Theorem.

Apply the quadratic formula to find the two roots that would set this quadratic polynomial to 0. The discriminant of this polynomial is (5^{2} - 4 \times 1 \times 6) = 1.

\begin{aligned}x_{1} &= \frac{-5 + \sqrt{1}}{2\times 1} \\ &= \frac{-5 + 1}{2} \\ &= -2\end{aligned}.

Similarly:

\begin{aligned}x_{2} &= \frac{-5 - \sqrt{1}}{2\times 1} \\ &= \frac{-5 - 1}{2} \\ &= -3\end{aligned}.

By the Factor Theorem, if x = x_{0} is a root of a polynomial, then (x - x_0) would be a factor of that polynomial. Note the minus sign between x and x_{0}.

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Verify that (x + 2)\, (x + 3) indeed expands to the original polynomial:

\begin{aligned}& (x + 2)\, (x + 3) \\ =\; & x^{2} + 2\, x + 3\, x + 6 \\ =\; & x^{2} + 5\, x + 6\end{aligned}.

4 0
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|4x−4(x+1)|=4

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Answer:

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