C = 0.11 mol
V = 5.65 L
n = ???
n = C*V
n = 0.11 * 5.65
n = 0.622 mols
1 mol of CaCl2 = 40 + 2*35.5 = 111 grams
0.622 mol = x
x = 111 * 0.622
x = 69.0 grams CaCl2
Based on location in the periodic table, fluorine (F) has chemical properties that are most similar to iodine.
In the periodic table, elements are classified in groups and periods. The elements in the same group are chemically similar and they have the same number of valence electrons. Elements in the same period have the same highest energy level.
Hence, when looking for an element that is most chemically similar to iodine, we have to consider the element that is in the same group with iodine.
Both fluorine are iodine are both in group 17 hence, fluorine is most chemically similar to iodine.
Learn more: brainly.com/question/11155928
Answer:
7.28 mol
Explanation:
2 NaOH + H₂SO₄ = 2 H₂O + Na₂SO₄ -------------------(1)
mole fraction for the reaction is;
2 : 1 = 2 : 1
Number of moles of H₂SO₄ = 7.28 mol
1 mol of H₂SO₄ shall form 1 mole of Na₂SO₄
therefore,
7.28 mol of H₂SO₄ shall form 7.28 mole of Na₂SO₄
