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Lynna [10]
2 years ago
9

Identify two characteristics of water that are a result of its molecular structure. Describe how each characteristic is related

to the molecular structure of water.
Chemistry
1 answer:
photoshop1234 [79]2 years ago
4 0

Answer:

Explained below

Explanation:

1) Hydrogen bonds are formed between molecules

All these is because the bonds are flexible in such a manner that in the liquid phase, the molecules are relatively close to each other.

However, it is also noted that the hexagonal arrangement of ice is formed the bonds will be locked in place which will result in the average distance between molecules actually increasing which in turn means given a result that ice is less dense than liquid water.

B) Water possesses a high boiling point: This is because the Hydrogen oxygen bond or O-H bonds are highly polar and the Hydrogen atoms in this bond are located at two corners of the tetrahedron shaped like bond shape which gives water it's high molecular polarity in which in turn makes the molecules to stick together.

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According to current theory, a major reason for bonding is
tatiyna
Covalent bond   a chemical bond formed by two electrons that are shared between two atoms
ionic bond<span>    a chemical bond formed by the electrostatic attraction between ions</span>
metallic bond<span>    a bond characteristic of metals in which mobile valence electrons are shared among positive nuclei in the metallic crystal</span>
6 0
2 years ago
Read 2 more answers
Aluminum foil is often incorrectly termed tin foil. If the density of tin is 7.28g/cm³,what is the thickness of a piece of tin f
leonid [27]

Answer:

15.0 µm

Step-by-step explanation:

Density = mass/volume

        D = m/V     Multiply each side by V

      DV = m        Divide each side by D

        V = m/D

Data:

m = 1.091 g

D = 7.28 g/cm³

 l = 10.0 cm

w = 10.0 cm

Calculation:

<em>(a) Volume of foil </em>

V = 1.091 g  × (1 cm³/7.28 g)

  = 0.1499 cm³

(b) <em>Thickness of foil </em>

The foil is a rectangular solid.

V  = lwh                            Divide each side by lw

h = V/(lw)

   = 0.1499/(10 × 10)

   = 1.50 × 10⁻³ cm           Convert to millimetres

   = 0.015 mm                  Convert to micrometres

   = 15.0 µm

The foil is 15.0 µm thick.

4 0
3 years ago
How many moles of ba(oh)2 are present in 275 ml of 0.200 m ba(oh)2?
DENIUS [597]
You have to put your attention to the unit of concentration. It is expressed in terms of molarity, which is represented in M. It is the number of moles solute per liter solution. So, you simply have to multiply the molarity with the volume in liters.

Volume = 275 mL * 1 L/1000 mL = 0.275 L
<em>Moles Ba(OH)₂ = (0.200 M)(0.275 L) = 0.055 mol</em>
6 0
3 years ago
In a constant‑pressure calorimeter, 60.0 mL of 0.300 M Ba(OH)2 was added to 60.0 mL of 0.600 M HCl. The reaction caused the temp
Zepler [3.9K]

Answer:

ΔH = 57.04 Kj/mole H₂O

Explanation:

60ml(0.300M Ba(OH)₂(aq) + 60ml(0.600M HCl(aq)

=> 0.06(0.3)mole Ba(OH)₂(aq) + 0.60(0.6)mole HCl(aq)

=> 0.018mole Ba(OH)₂(aq) + 0.036mole HCl(aq)

=> 100% conversion of reactants => 0.018mole BaCl₂(aq) + 0.036mole H₂O(l) + Heat

ΔH = mcΔT/moles H₂O <==> Heat Transfer / mole H₂O

=(120g)(4.0184j/g°C)(27.74°C - 23.65°C)/(0.036mole H₂O)

ΔH = 57,042 j/mole H₂O = 57.04 Kj/mole H₂O

3 0
3 years ago
Balance all the equations
siniylev [52]

Answer:

Balancing Chemical Equations

Balance the equations below:

1) __1__ N2 + __3__ H2      >       _2__ NH3

2) __2__ KClO3  >⮴ __2__ KCl + __3__ O2

3) __2__ NaCl + __1__ F2 ⮴ __2__ NaF + __1__ Cl2

4) __2__ H2 + __1__ O2 ⮴ __2__ H2O

5) __1__ Pb(OH)2 + __2__ HCl ⮴ __2__ H2O + __1__ PbCl2

6)__2__ AlBr3 + __3__ K2SO4 ⮴ __6__ KBr + __1__ Al2(SO4)3

7) __1__ CH4 + __2__ O2 ⮴ __1__ CO2 + __2__ H2O

8) _1___ C3H8 + _5___ O2 ⮴ __3__ CO2 + __4__ H2O

9) __2__ C8H18 + __25__ O2 ⮴ __16__ CO2 + __18__ H2O

10) __1__ FeCl3 + __3__ NaOH ⮴ __1__ Fe(OH)3 + __3__NaCl

11) __4__ P + __5__O2 ⮴ __2__P2O5

12) __2__ Na + __2__ H2O ⮴ __2__ NaOH + __1__H2

13) __2__ Ag2O ⮴ __4__ Ag + __1__O2

14) __1__ S8 + __12__O2 ⮴ __8__ SO3

15) _6___ CO2 + _6___ H2O ⮴ __1__ C6H12O6 + __6__O2

16) ___1_ K + __1__ MgBr ⮴ __1__ KBr + __1__ Mg

17) __2__ HCl + __1__ CaCO3 ⮴ __1__ CaCl2 + __1__H2O + __1__ CO2

18) __1__ HNO3 + __1__ NaHCO3 ⮴ __1__ NaNO3 + __1__ H2O + _1___ CO2

19) _2___ H2O + __1__ O2 ⮴ __2__ H2O2

20) __2__ NaBr + __1__ CaF2 ⮴ __2__ NaF + __1__ CaBr2

Explanation:

5 0
3 years ago
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