First we must write a balanced chemical equation for this reaction
![Na_2CO_3 _(_a_q_)+ 2HNO_3_(_a_q_) \implies 2NaNO_3_(_s_) + CO_2_(_g_) + H_2O_(_l_)](https://tex.z-dn.net/?f=Na_2CO_3%20_%28_a_q_%29%2B%202HNO_3_%28_a_q_%29%20%5Cimplies%202NaNO_3_%28_s_%29%20%2B%20CO_2_%28_g_%29%20%2B%20H_2O_%28_l_%29)
The mole ratio for the reaction between
and
is 1:2. This means 1 moles of
will neutralize 2 moles
. Now we find the moles of each reactant based on the mass and molar mass.
![2500g HNO_3 \times \frac{mol}{63.01g\ HNO_3} = 39.67 mol\ HNO_3](https://tex.z-dn.net/?f=2500g%20HNO_3%20%5Ctimes%20%5Cfrac%7Bmol%7D%7B63.01g%5C%20HNO_3%7D%20%3D%2039.67%20mol%5C%20HNO_3)
![2000g\ Na_2CO_3 \times \frac{mol}{105.99g \ Na_2CO_3} = 18.87 mol\ Na_2CO_3](https://tex.z-dn.net/?f=2000g%5C%20Na_2CO_3%20%5Ctimes%20%5Cfrac%7Bmol%7D%7B105.99g%20%5C%20Na_2CO_3%7D%20%3D%2018.87%20mol%5C%20Na_2CO_3)
![\frac{18.87 mol Na_2CO_3}{39.67\ HNO_3} = \frac{1 molNa_2CO_3}{2 mol HNO_3}](https://tex.z-dn.net/?f=%5Cfrac%7B18.87%20mol%20Na_2CO_3%7D%7B39.67%5C%20HNO_3%7D%20%3D%20%5Cfrac%7B1%20molNa_2CO_3%7D%7B2%20mol%20HNO_3%7D)
The
was enough to neutralize the acid because 18.87:39.67 is the same as 1:2 mol ratio.
Answer:
Option B.
Explanation:
As any reaction of combustion, the O₂ is a reactant and the products are CO₂ and H₂O. Combustion reaction for ethane is:
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
So 2 moles of ethane react with 7 moles of oxygen to make 4 moles of dioxide and 6 moles of water.
Then 2 moles of ethane will produce 4 moles of CO₂
hope it helps please brainliest
<u>Answer: </u>The correct statement is X is the effective nuclear charge, and it increases across a period.
<u>Explanation:</u>
We are given that:
X = number of protons − number of core electrons
Effective nuclear charge is defined as the actual nuclear charge (Z = number of protons) minus the screening effect caused by the electrons present between nucleus and valence electrons. These electrons are the core electrons.
The formula used for the calculation of effective nuclear charge given by Slater is:
![Z^*=Z-\sigma](https://tex.z-dn.net/?f=Z%5E%2A%3DZ-%5Csigma)
where,
= effective nuclear charge
Z = atomic number or actual nuclear charge or number of protons
= Screening constant
The effective nuclear charge increases as we go from left to right in a period because nuclear charge increases with no effective increase in screening constant.
Hence, the correct answer is X is the effective nuclear charge, and it increases across a period.