Answer:
sodium hexachloroplatinate(IV)- Na2[PtCl6]
dibromobis(ethylenediamine)cobalt(III) bromide- [Co(en)2Br2]Br
pentaamminechlorochromium(III) chloride-[Cr(NH3)5Cl]Cl2
Explanation:
The formulas of the various coordination compounds can be written from their names taking cognisance of the metal oxidation state as shown above. The oxidation state of the metal will determine the number of counter ions present in the coordination compound.
The number ligands are shown by subscripts attached to the ligand symbols. Remember that bidentate ligands such as ethylenediamine bonds to the central metal ion via two donors.
Answer:
1) 17.5 mL
Explanation:
Hello,
In this case, the reaction between sulfuric acid and potassium hydroxide is:
![H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O](https://tex.z-dn.net/?f=H_2SO_4%2B2KOH%5Crightarrow%20K_2SO_4%2B2H_2O)
In such a way, we notice a 1:2 molar ratio between the acid and the base, therefore, at the equivalence point we have:
![2*n_{acid}=n_{base}](https://tex.z-dn.net/?f=2%2An_%7Bacid%7D%3Dn_%7Bbase%7D)
And in terms of concentrations and volumes:
![2*M_{acid}V_{acid}=M_{base}V_{base}](https://tex.z-dn.net/?f=2%2AM_%7Bacid%7DV_%7Bacid%7D%3DM_%7Bbase%7DV_%7Bbase%7D)
Thus, we solve for the volume of acid:
![V_{acid}=\frac{M_{base}V_{base}}{2*M_{acid}} =\frac{35mL*1.5M}{2*1.5M} \\\\V_{acid}=17.5mL](https://tex.z-dn.net/?f=V_%7Bacid%7D%3D%5Cfrac%7BM_%7Bbase%7DV_%7Bbase%7D%7D%7B2%2AM_%7Bacid%7D%7D%20%3D%5Cfrac%7B35mL%2A1.5M%7D%7B2%2A1.5M%7D%20%5C%5C%5C%5CV_%7Bacid%7D%3D17.5mL)
Best regards.
I think it would be B hope not too late
Answer:
Iron + copper(II) sulphate → iron sulphate + copper
Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)
copper + silver nitrate → copper nitrate + silver
Cu (s) + 2AgNO3 (aq) → Cu(NO3)2 (aq) + 2Ag (s)