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3 years ago

Describe a real world situation that uses the variable x the expression 1/2x when the value of x is not known.

Mathematics

1 answer:

Airida [17]3 years ago

6 0

Um well its quite common when going to the store and something is 50% off

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28,18,8,-2 is this arithmetic ?

Tresset [83]

Answer:

yes it is arithmetic because:

28 - 10= 18

18 - 10= 8

8 - 10= -2

it keeps decreasing by the same number (10). Therefore, it is arithmetic.

3 0

3 years ago

....................

antiseptic1488 [7]

The answer is (A), or 8.

6 0

3 years ago

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Ik rp because the i forgot the sc

Stels [109]

Answer:

Step-by-step explanation:

This is a geometric mean problem...a ratio. The geometric mean is the height of the triangle, 6. To solve:

$\frac{x}{6} =\frac{6}{3}$ and cross multiply to solve for x:

3x = 36 so

x = 12

6 0

1 year ago

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Which two expressions are equal?

guapka [62]

Answer: C and d my guy becuz u have to calculate all and see answers moomoo

4 0

3 years ago

The object on the right is made from a square-based pyramid joined to a cuboid.

spayn [35]

Answer:

Density of steel = 80.73 gm/ $cm^3$

Step-by-step explanation:

The figure is made up of cuboid and square pyramid.

Height of cuboid, h = 9 cm

Length of cuboid, l = 6 cm

Width of cuboid, w = 6 cm

Volume of cuboid is given by the formula:

$V_{Cuboid} = l \times w \times h$

$V_{Cuboid} = 6 \times 6 \times 9\\\Rightarrow V_{Cuboid} = 324\ cm^3$

Density of Wood , $D_{Cuboid}$ = 0.68g/ $cm^3$

We know that formula of Density is:

$Density = \dfrac{Weight}{Volume}$

$D_{Cuboid} = \dfrac{W_{Cuboid}}{V_{Cuboid}}\\\Rightarrow W_{Cuboid} = V_{Cuboid} \times D_{Cuboid}$

Putting the values:

$W_{Cuboid} = 324 \times 0.68 = 220.32\ gm$

Total weight = $W_{Cuboid} + W_{Pyramid}$

970 = 220.32 $+ W_{Pyramid}$

$W_{Pyramid}$ = 749.68 gm

Volume of pyramid is given as:

$V_{Pyramid}= \dfrac{1}{3} \times \text{Area of Base} \times \text{Vertical Height}$

Base is a square with side 6 cm

$V_{Pyramid}= \dfrac{1}{3} \times 6 \times 6 \times (17 -9)\\V_{Pyramid}= 96\ cm^3$

Density of Steel/Pyramid:

$D_{Pyramid} = \dfrac{W_{Pyramid}}{V_{Pyramid}}\\\Rightarrow D_{Pyramid} = \dfrac{749.68}{96}\\\Rightarrow D_{Pyramid} = 80.73\ gm/cm^3$

5 0

3 years ago