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VLD [36.1K]
2 years ago
10

Time period of a simple pendulum is measured at karachi, what change will occur in the time period ,if it is measured on mount e

verest ,explain?
Physics
1 answer:
iren [92.7K]2 years ago
3 0
The period T of a simple pendulum is given by:

T = 2\pi \sqrt{ \frac{m}{g} }

where m is the mass of the pendulum and g is the gravitational acceleration.

The period of the pendulum will increase when the gravitational acceleration decreases.
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The length of a wooden rod is 25.5 cm. What is this length in:<br>(a) millimetres?<br>(b) metres?​
larisa86 [58]

Answer:

(a)255mm \\ (b)0.255m

Explanation:

(a)1cm = 10mm \\ 25.5cm = x

Cross multiply

1x = 25.5 \times 10 \\ x = 255mm

(b)100cm = 1m \\ 25.5cm = x

cross multiply

100x = 25.5 \\  \frac{100x}{100}  =  \frac{25.5}{100}  \\ x = 0.255m

hope this helps

brainliest appreciated

good luck! have a nice day!

4 0
3 years ago
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WHAT IS A INNATE RESPOSE?/EXAMPLE AND ANSWER
san4es73 [151]
An innate response is something that you are born knowing how to do or becomes natural after it is done the first time, an example would be breathing you are born knowing how to breath naturally.
5 0
2 years ago
A 1.40 mH inductor and a 1.00 µF capacitor are connected in series. The current in the circuit is described by I = 14.0 t, where
4vir4ik [10]

Answer:

Explanation:

Inductance L = 1.4 x 10⁻³ H

Capacitance C = 1 x 10⁻⁶ F

a )

current I = 14 .0 t

dI / dt  = 14

voltage across inductor

= L dI / dt

= 1.4 x 10⁻³ x 14

= 19.6 x 10⁻³ V

= 19.6 mV

It does not depend upon time because it is constant at 19.6 mV.

b )

Voltage across capacitor

V = ∫ dq / C

= 1 / C ∫ I dt  

= 1 / C ∫ 14 t dt

1 / C x 14 t² / 2

= 7 t² / C

= 7 t² / 1 x 10⁻⁶

c ) Let after time t energy stored in capacitor becomes equal the energy stored in capacitance

energy stored in inductor

= 1/2 L I²

energy stored in capacitor

= 1/2 CV²

After time t

1/2 L I² = 1/2 CV²

L I² =  CV²

L x ( 14 t )² = C x  ( 7 t² / C )²

L x 196 t² = 49 t⁴ / C

t² = CL x 196 / 49

t = 74.8 μ s

After 74.8 μ s energy stored in capacitor exceeds that of inductor.

7 0
2 years ago
Urgent if earths gravitational field strength is 10 N/kg how many newtons does a 30kg object weigh
egoroff_w [7]

weight of 30 Kg object= 300 N

Explanation:

Weight= m I

m= mass=30 kg

I= gravitational filed strength= 10 N/kg

weight=30 (10)

weight=300 N

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What do we measure energy in
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Energy is measured by joule(j)
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