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VLD [36.1K]
3 years ago
10

Time period of a simple pendulum is measured at karachi, what change will occur in the time period ,if it is measured on mount e

verest ,explain?
Physics
1 answer:
iren [92.7K]3 years ago
3 0
The period T of a simple pendulum is given by:

T = 2\pi \sqrt{ \frac{m}{g} }

where m is the mass of the pendulum and g is the gravitational acceleration.

The period of the pendulum will increase when the gravitational acceleration decreases.
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Find the ratio of the new/old periods of a pendulum if the pendulum were transported from earth to the moon, where the accelerat
vichka [17]
The period of a pendulum is given by
T=2 \pi  \sqrt{ \frac{L}{g} }
where L is the pendulum length and g is the gravitational acceleration.

We can write down the ratio between the period of the pendulum on the Moon and on Earth by using this formula, and we find:
\frac{T_m}{T_e} =  \frac{2 \pi  \sqrt{ \frac{L}{g_m} } }{2 \pi  \sqrt{ \frac{L}{g_e} } }=    \sqrt{ \frac{g_e}{g_m} }
where the labels m and e refer to "Moon" and "Earth".

Since the gravitational acceleration on Earth is g_e = 9.81 m/s^2 while on the Moon is g_m=1.63 m/s^2, the ratio between the period on the Moon and on Earth is
\frac{T_m}{T_e}= \sqrt{ \frac{g_e}{g_m} }= \sqrt{ \frac{9.81 m/s^2}{1.63 m/s^2} }=2.45

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2 years ago
Any help would be highly appreciated, preferably with steps too!
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Answer:

Help with what:?

Explanation:

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