Name the three parts of the atom.

Each mineral group has a distinctive chemical feature such as

disa [49]

Answer:

A

Explanation:

6 0

2 years ago

BY ANSWERING THIS QUESTION UR PUTTING IT ON UR MOM's LIFE THAT U WON'T STEAL MY POINTS.

Yakvenalex [24]

Answer:

$T_2=-125.58\°C$

Explanation:

Hello!

In this case, considering the Gay-Lussac's law which describes the pressure-temperature behavior as a directly proportional relationship by holding the volume as constant, we write:

$\frac{T_1}{P_1} =\frac{T_2}{P_2}$

Whereas solving for the final temperature T2, we get:

$T_2=\frac{T_1P_2}{P_1}$

Thus, we plug in the given data (temperature in Kelvins) to obtain:

$T_2=\frac{(22+273.15)K*1.75atm}{3.50atm} \\\\T_2=147.58K-273.15\\\\T_2=-125.58\°C$

Best regards!

3 0

2 years ago

Draw the circuit symbol that would represent the 9V battery

lora16 [44]

I hope this picture helps

3 0

2 years ago

Which of the following represents the smallest mass? I.) 23 cg II.) 2.3 x 10-3 μg III.) 0.23 mg IV.) 0.23 g V.) 2.3 x 10-2 kg

jenyasd209 [6]

The smallest mass among the choices is Choice (ii):2.3 x 10-3 μg

This is so because, the prefix μ signifies a factor of 10^-6.

For choice I:

23 cg means 23 centigrams

In essence = 0.23grams

For choice II:

2.3 × 10-3 μg means 2.3 × 10-9 grams

For choice III:

0.23 mg means 0.23 × 10-3 grams

For choice IV:

0.23 grams simply means 0.23grams

For choice V:

2.3 × 10-2 kg means 23 grams

Ultimately, Choice II represents the smallest mass.

Read more;

brainly.com/question/17192728

7 0

2 years ago

Given the two reactions H2S(aq)⇌HS−(aq)+H+(aq), K1 = 9.57×10−8, and HS−(aq)⇌S2−(aq)+H+(aq), K2 = 1.46×10−19, what is the equilib

Dvinal [7]

Answer: The value of $K_c$ for the final reaction is $7.16\times 10^{25}$

Explanation:

The given chemical equations follows:

Equation 1: $H_2S(aq.)\rightleftharpoons HS^-(aq.)+H^(aq.);K_1$

Equation 2: $HS^-(aq.)\rightleftharpoons S^{2-}(aq.)+H^(aq.);K_2$

The net equation follows:

$S^{2-}(aq.)+2H^+(aq.)\rightleftharpoons H_2S(aq.);K_c$

As, the net reaction is the result of the addition of reverse of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of inverse of first equilibrium constant and the inverse of second equilibrium constant.

The value of equilibrium constant for net reaction is:

$K_c=\frac{1}{K_1}\times \frac{1}{K_2}$

We are given:

$K_1=9.57\times 10^{-8}$

$K_2=1.46\times 10^{-19}$

Putting values in above equation, we get:

$K_c=\frac{1}{(9.57\times 10^{-8})}\times \frac{1}{(1.46\times 10^{-19})}=7.16\times 10^{25}$

Hence, the value of $K_c$ for the final reaction is $7.16\times 10^{25}$

5 0

3 years ago