From the calculations, the half life of the material is 6.5 days.
<h3>What is radioactivity?</h3>
The term radioactivity has to do with the spontaneous disintegration of a specie.
Uisng the formula;
N=Noe^-kt
N= amount at time t = 0.135 Ci or 4.995 ×10^9 Bq
No = amount initially present = 1.75 x 10^12 Bq
k = rate constant = ?
t = time taken = 55 days
Hence;
4.995 ×10^9 = 1.75 x 10^12e^-55k
4.995 ×10^9/1.75 x 10^12 = e^-55k
2.85 * 10^-3 = e^-55k
ln2.85 * 10^-3 = -55k
k = ln2.85 * 10^-3/-55
k = 0.1066 day-1
Half life = 0.693/ 0.1066 day-1
= 6.5 days
Learn more about radioactivity:brainly.com/question/1770619
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Answer:
The vacuum would stop
Explanation:
if the lid opened the there would be no more pressure therefor no vacuum.
- Naturally occurring
- Inorganic
- Solid
- Definite chemical composition
- Ordered internal structure
A mineral has to be naturally occurring. Coal is not a mineral because it is carbon-based and comes from fossilized plants. Glass is non-crystalline solid.
In order to balance both of the reactions you need to make sure that both sides of the reaction have the same number of atoms for each atom in order to follow conservation of mass.
KCl+F₂→KF+Cl₂
Notice how in the above reaction there are two chlorine atoms on the products side (right side) and only one atom of chlorine on the reactants side (left side). you want both the reactants and products side to have the same amount chlorine and to do this multiply KCl by 2. Fluorine however, has 2 atoms on the reactant side and 1 atom on the product side. to fix this multiply KF by 2. <span>Therefore the balanced reaction is: 2KCl+F₂→2KF+Cl₂
</span>notice how both sides of the reaction have equal numbers of each atom.
Mg+HCl→MgCl₂+H₂
the above reaction has 2 atoms of H on the products side and only 1 atom of H on the reactants side. That means you have to multiply HCl by 2. Now you have the equation Mg+2HCl→MgCl₂+H₂. As you can see now we have equal numbers of all the atoms on both sides which means that that is the balanced equation.
I hope this helps. Let me know if you have any further questions or need anything to be clarified.