1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
shepuryov [24]
3 years ago
11

PLZZZZZ HELP MEEEEEE

Chemistry
1 answer:
Masja [62]3 years ago
4 0

Answer:

0.0745 mole of hydrogen gas

Explanation:

Given parameters:

Number of H₂SO₄ = 0.0745 moles

Number of moles of Li = 1.5107 moles

Unknown:

Number of moles of H₂ produced = ?

Solution:

To solve this problem, we have to work from the known specie to the unknown one.

The known specie in this expression is the sulfuric acid,  H₂SO₄. We can compare its number of moles with that of the unknown using a balanced chemical equation.

   Balanced chemical equation:

                    2Li   +     H₂SO₄   →   Li₂SO₄   +   H₂

 From the balanced equation;

     

Before proceeding, we need to obtain the limiting reagent. This is the reagent whose given proportion is in short supply. It determines the extent of the reaction.

           2 mole of Li reacted with 1 mole of  H₂SO₄

          1.5107 mole of lithium will react with \frac{1.5107}{2}  = 0.7554mole of H₂SO₄

But we were given 0.0745 moles,

This suggests that the limiting reagent is the sulfuric acid because it is in short supply;

   

   since 1 mole of sulfuric acid produced 1 mole of hydrogen gas;

    0.0745 mole of sulfuric acid will produce 0.0745 mole of hydrogen gas

You might be interested in
Is mass conserved when 50 g of sugar undergoes a physical change?
Lena [83]
Yes, mass never changes. No exceptions.
6 0
3 years ago
Read 2 more answers
How many valence electrons does a carbon atom have
KATRIN_1 [288]
4.
__________________
4 0
3 years ago
Read 2 more answers
From the lists of available reagents select the one(s) you would use to in a preparation of acetophenone (phenyl methyl ketone)
VARVARA [1.3K]

Answer:

Step 1) hydrolysis using NaOH/H2O to form benzylalcohol

Step2) oxidation to Carboxylic acid using KMnO4 followed by decarboxylation to form benzene

3) friedel craft acylation using CH3COCl/AlCl3

Explanation:

The above 3 steps will yield acetophenone from methylbenzoate

3 0
3 years ago
If one parent has sickle cell anemia and the other parent is a carrier, what is the possibility that their child will have sickl
earnstyle [38]
It’s a 50 50 chance unless one parent has a dominate gene
5 0
3 years ago
Bromine is less electronegative than chlorine, yet methyl bromide and methyl chloride have very similar dipole moments. why? sel
diamong [38]
Bromine is less electronegative than chlorine, yet methyl bromide and methyl chloride have very similar dipole moments. This is because the bond distance in methyl bromide is more due to the large size of bromine atom.
Dipole moment is calculated by multiplying the charge on the atom with the bond distance.
4 0
3 years ago
Other questions:
  • Using the equation PCl5(g)=PCl3(g)+Cl2(g), if PCl5 is removed, what will the equilibrium shift?
    9·1 answer
  • What is the oxidation number for iodine in Mg(IO3)2 ?
    13·2 answers
  • If 15.60 g of a hydrated compound is heated in an oven for several hours, its mass drops to 8.63 g. Assuming that the reduction
    12·2 answers
  • The wastewater solution from a factory containing high levels of salts needs to be diluted before it can be released into the en
    13·1 answer
  • How many electrons can the n=4 shell hold?<br> a. 8b.16c.32d.64?
    11·2 answers
  • What is the mass of one mole of calcium carbonate
    5·2 answers
  • Please help me I am confused
    13·2 answers
  • 5. The formula unit of calcium sulfide is :<br>(1 Point)<br>OCa, S,<br>o Ca₂S<br>O Ca23<br>O Cas​
    8·1 answer
  • TRUE OR FALSE? Alloys are used more than pure metals because they are generally softer and less likely to react with air or wate
    8·1 answer
  • Ag + HCl --&gt; ?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!