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3 years ago

Which of the following best describes a property of water?

Physics

1 answer:

NNADVOKAT [17]3 years ago

4 0

Answer:

C. weak cohesive forces exist between its molecules.

Explanation:

This is because water has less intermolecular forces than solids, but more than gases. Also their cohesive forces is low.

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The smallest shift you can reliably measure on the screen is about 0.2 grid units. This shift corresponds to the precision of po

creativ13 [48]

Answer:

The distance is $d = 1.5 *10^{15} \ km$

Explanation:

From the question we are told that

The smallest shift is $d = 0.2 \ grid \ units$

Generally a grid unit is $\frac{1}{10}$ of an arcsec

This implies that 0.2 grid unit is $k = \frac{0.2}{10} = 0.02 \ arc sec$

The maximum distance at which a star can be located and still have a measurable parallax is mathematically represented as

$d = \frac{1}{k}$

substituting values

$d = \frac{1}{0.02}$

$d = 50 \ parsec$

Note $1 \ parsec \ \to 3.26 \ light \ year \ \to 3.086*10^{13} \ km$

So $d = 50 * 3.08 *10^{13}$

$d = 1.5 *10^{15} \ km$

3 0

3 years ago

A crate of mass 50kg is pushed along a floor with a force of 20N for a distance of

PSYCHO15rus [73]

Answer:

F=50kg

D=5m

W=FD

therefore work done is 250Nm

8 0

2 years ago

Holes drilled several kilometers into Earth’s crust provide direct evidence about Earth’s interior in the form of

ivanzaharov [21]

C I hope this helps cccccccccccccccccccc

6 0

3 years ago

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A gas is placed in a storage tank at a pressure of 49.2 atm at 39.0C . As a safety device, a small metal plug in the tank is mad

Amiraneli [1.4K]

Answer:

The maximum pressure that will be attained in the tank before the plug melts and releases gas should be less than 74.26 atm.

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1\text{ and }T_1$ are the initial pressure and temperature of the gas.

$P_2\text{ and }T_2$ are the final pressure and temperature of the gas.

We are given:

$P_1=49.2 atm\\T_1=39.0^oC = 312.15 K\\P_2=?\\T_2=198^oC=471.15 K$

Putting values in above equation, we get:

$\frac{49.2atm }{312.15 K}=\frac{P_2}{471.15 K}\\\\P_2=74.26 atm$

The maximum pressure that will be attained in the tank before the plug melts and releases gas should be less than 74.26 atm.

4 0

3 years ago

Please I need the answer right now will mark you brainliest

Dmitrij [34]

Answer:

Explanation:

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3 0

2 years ago

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