<em>v</em>² - <em>u</em>² = 2 <em>a</em> ∆<em>x</em>
where <em>u</em> = initial velocity (27 m/s), <em>v</em> = final velocity (0), <em>a</em> = acceleration (-8 m/s², taken to be negative because we take direction of movement to be positive), and ∆<em>x</em> = stopping distance.
So
0² - (27 m/s)² = 2 (-8 m/s²) ∆<em>x</em>
∆<em>x</em> = (27 m/s)² / (16 m/s²)
∆<em>x</em> ≈ 45.6 m
Answer:
16916.4 V
Explanation:
Electric potential: This is the work done in bringing a unit positive charge from infinity to that point in against the action of the field. The S.I unit of Electric potential is V.
mathematically, Electric potential can be expressed as
P = E×d ....................................... Equation 1.
Where P = Electric potential, E = Electric Field, d = distance/height of the level at the top of the Washington Monument.
Given: E = 100 V/m, d = 555 ft = 555×0.3048 m = 169.164 m.
Substitute into equation 1
P = 100×169.164
P = 16916.4 V.
Thus the potential difference = 16916.4 V.
Answer:
False only direction not weight.
Explanation:
Assume theres no air reaistance. (or else the ball will oppose the motion of the ball, hence decrease the velocity increase)
see if there are any problems!
Answer:
Explanation:
Given
When we drop an object from height , suppose h
it takes time T
using equation of motion
where
here 
because it dropped from a certain height
When height is increases to three times of original height
i.e. 
then time period becomes
