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Mariulka [41]
3 years ago
11

Select all of the answers that apply.

Physics
2 answers:
Kruka [31]3 years ago
6 0
The answer is letter A. meteorite bombardment.
During the Earth's earliest beginning, it went through a period of catastrophic and intense formation. By 3-8- 4.1 billion years ago, Earth's atmosphere was never the same as today. This is because of its formation during the pre-Cambrian period whereby t<span>he Earth formed under so much heat and pressure that it formed as a molten planet.
</span>

Earth was bombarded continuously by the remnants of the dust and debris — like asteroids, meteors and comets — until it formed into a solid sphere, pulled into orbit around the sun and began to cool down during the Hellish period (4.5 to 3.8 billion years ago).

<span> </span>.To know more of this topic, see attached file.

 

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Helga [31]3 years ago
4 0

Answer: meteorite bombardment

Explanation: This is because of its formation during the pre-Cambrian period whereby the Earth formed under so much heat and pressure that it formed as a molten planet.

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State the reason and tell whether true or false. The SPEED OF LIGHT IS THE SAME IN ALL MEDIA.​
Sphinxa [80]

Answer:

<em>The statement is true .</em>

Explanation:

<em>I hope this helps.</em>

4 0
4 years ago
One litre of crude oil weighs 9.6N. Calculate its specific weight, density and specific gravity.​
Zepler [3.9K]

Answer:

The answer is "\bold{9600 \frac{N}{m^3}, 978.59 \frac{kg}{m^3}, and \ 0.978}"

Explanation:

Given:

\to v=1\ liter= 10^{-3} \ m^3\\\\\to  w= 9.6 \ N\\

calculation:

Specific \ weight =\frac{w}{v}=\frac{9.6}{10^{-3}}=9600 \frac{N}{m^3} \\\\w=mg\\\\m= \frac{w}{g}=\frac{9.6}{9.81}=0.9785\ kg\\\\\rho\ (density)=\frac{m}{v}=\frac{0.9785}{10^{-3}}=978.59 \frac{kg}{m^3}\\\\specific \ gravity = \frac{\prho \ obj}{\rho w}=\frac{978.54}{1000}=0.978

4 0
3 years ago
a 65 kg skater at rest on a frictionless rink throws a 2 kg ball, giving the ball a velocity of 7 m/s. What is the velocity of t
gayaneshka [121]
The answer to your question is 33
8 0
3 years ago
An ion in a mass spectrometer follows a semicircular path of radius 14.8. What is the distance it travels?
aleksklad [387]

The circumference of a circle is (2π · the circle's radius).

The length of a semi-circle is  (1π · the circle's radius) =

                                                 (π · 14.8) = 46.5 (rounded)

(The unit is the same as whatever the unit of the  14.8  is.)

7 0
3 years ago
Read 2 more answers
An object with a mass m slides down a rough 370 inclined plane where the coefficient of kinetic friction is 0.20. If the plane i
Svetllana [295]

Answer:

v \approx 9.312\,\frac{m}{s}

Explanation:

The Free Body Diagram of the system is presented in the image attached below. The final speed is determined by means of the Principle of Energy Conservation and the Work-Energy Theorem:

K_{A} + U_{g,A} = K_{B} + U_{g,B} + W_{loss}

K_{B} = K_{A} + U_{g,A}-U_{g,B} - W_{loss}

\frac{1}{2}\cdot m \cdot v^{2} = m\cdot g \cdot s\cdot \sin \theta - \mu_{k}\cdot m \cdot g \cdot s \cos \theta

\frac{1}{2}\cdot v^{2} = g\cdot s \cdot (\sin \theta - \mu_{k}\cdot \cos \theta)

v = \sqrt{2\cdot g \cdot s \cdot (\sin \theta - \mu_{k}\cdot \cos \theta)}

v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (10\,m)\cdot (\sin 37^{\textdegree} - 0.2\cdot \cos 37^{\textdegree})}

v \approx 9.312\,\frac{m}{s}

3 0
3 years ago
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