Anthropology. It focuses on human behavior.
The angular speed can be solve using the formula:
w = v / r
where w is the angular speed
v is the linear velocity
r is the radius of the object
w = ( 5 m / s ) / ( 5 cm ) ( 1 m / 100 cm )
w = 100 per second
Answer:
An example of kinetic energy is a <u><em>car coming to a stop</em></u>
Explanation:
Kinetic energy is the energy that a body or system possesses due to its movement. In physics this energy is defined as the amount of work necessary to accelerate a body of a certain mass and in rest position, until reaching a certain speed. This energy obtained will remain unchanged as long as this body does not vary its speed. That is, kinetic energy measures how many changes an object that is moving can cause.
<u><em>An example of kinetic energy is a car coming to a stop</em></u>. If the car is moving and comes to a stop, there is a change in speed, therefore in movement, eventually producing a change in kinetic energy. This energy depends on the mass of the body, in this case the car, and the speed. As the speed decreases, the kinetic energy will decrease.
Answer:
P=740 KPa
Δ=7.4 mm
Explanation:
Given that
Diameter of plunger,d=30 mm
Diameter of sleeve ,D=32 mm
Length .L=50 mm
E= 5 MPa
n=0.45
As we know that
Lateral strain
![\varepsilon _t=\dfrac{D-d}{d}](https://tex.z-dn.net/?f=%5Cvarepsilon%20_t%3D%5Cdfrac%7BD-d%7D%7Bd%7D)
![\varepsilon _t=\dfrac{32-30}{30}](https://tex.z-dn.net/?f=%5Cvarepsilon%20_t%3D%5Cdfrac%7B32-30%7D%7B30%7D)
![\varepsilon _t=0.0667](https://tex.z-dn.net/?f=%5Cvarepsilon%20_t%3D0.0667)
We know that
![n=-\dfrac{\epsilon _t}{\varepsilon _{long}}](https://tex.z-dn.net/?f=n%3D-%5Cdfrac%7B%5Cepsilon%20_t%7D%7B%5Cvarepsilon%20_%7Blong%7D%7D)
![\varepsilon _{long}=-\dfrac{\epsilon _t}{n}](https://tex.z-dn.net/?f=%5Cvarepsilon%20_%7Blong%7D%3D-%5Cdfrac%7B%5Cepsilon%20_t%7D%7Bn%7D)
![\varepsilon _{long}=-\dfrac{0.0667}{0.45}](https://tex.z-dn.net/?f=%5Cvarepsilon%20_%7Blong%7D%3D-%5Cdfrac%7B0.0667%7D%7B0.45%7D)
![\varepsilon _{long}=-0.148](https://tex.z-dn.net/?f=%5Cvarepsilon%20_%7Blong%7D%3D-0.148)
So the axial pressure
![P=E\times \varepsilon _{long}](https://tex.z-dn.net/?f=P%3DE%5Ctimes%20%5Cvarepsilon%20_%7Blong%7D)
![P=5\times 0.148](https://tex.z-dn.net/?f=P%3D5%5Ctimes%200.148)
P=740 KPa
The movement in the sleeve
![\Delta =\varepsilon _{long}\times L](https://tex.z-dn.net/?f=%5CDelta%20%3D%5Cvarepsilon%20_%7Blong%7D%5Ctimes%20L)
![\Delta =0.148\times 50](https://tex.z-dn.net/?f=%5CDelta%20%3D0.148%5Ctimes%2050)
Δ=7.4 mm
Answer:
2π/[28 x (10^-3)]
Explanation:
Angular speed : ω=2π/T
T = 28ms = 28 x (10^-3) s
Angular speed = 2π/[28 x (10^-3)]