The time constant determines how long it takes for the capacitor to charge.
To find the answer, we have to know more about the time constant of the capacitor.
<h3>What is time constant?</h3>
- The time it takes for a capacitor to discharge 36.8% of its charge in a discharging circuit or charge up to 63.2% of its maximum capacity in a charging circuit, given that it has no initial charge, is the time constant of a resistor-capacitor series combination.
- The circuit's reaction to a step-up (or constant) voltage input is likewise determined by the time constant.
- As a result, the time constant determines the circuit's cutoff frequency.
Thus, we can conclude that, the time constant determines how long it takes for the capacitor to charge.
Learn more about the time constant here:
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A = 1.15m/s2, Vf = 80.0km/h --> we need it in m/s, so:
Vf = 80km/h × 1000m/1km × 1h/3600s
= 22.22m/s
Top speed = Vf, initial speed = Vi
time (t) = V(Vf-Vi) ÷ a
t = (22.22-0)m/s ÷ 1.15m/s2
t = 22.22m/s × s2/1.15m
= 19.32 seconds
Answer:
Explanation:
Suppose v is the initial velocity and 
is the angle of inclination
distance traveled in vertical direction in t=1 s
When gravity is present
where 
here initial velocity is v\sin \theta [/tex] so
In absence of gravity
<span>-Mass (kg)
-Velocity (m/s)</span>
