Answer:
Its speed decreases.
Explanation:
When light enters into water, its speed decreases (as well as its frequency). This is the reason why refraction (the bending of light when it changes media) occurs.
This can be proven mathematically.
Given that the refractive index of water is 4/3, we know that refractive index is the ratio of the speed of light in a vacuum to the speed of light in another medium.
Therefore,
4/3 = (speed of light in vacuum) / (speed of light in water)
Speed of light in a vacuum is 3 * 10^8. Hence,
Speed of light in water is:
v = (3 * 10^8) / (4/3)
v = 2.25 * 10^8 m/s
As we can see, the speed of light decreases in water.
<span>It is called a lunar eclipse</span>
Because as energy flows some energy goes away because when it moves it use some energy!Think of it like....An Ice cube!If you put it on the table it starts to move and the move it move the more(energy)it uses so after time the ice is not as big as before.
I hope this helps-Karma Cosmos
Answer:
a) 1321.45 N
b) 1321.45 N
c) 2.66 m/s^2
d) 2.21*10^-22 m/s^2
Explanation:
Hello!
First of all, we need to remember the gravitational law:
Were
G = 6.67428*10^-11 N(m/kg)^2
m1 and m2 are the masses of the objects
r is the distance between the objects.
In the present case
m1 = earth's mass = 5.9742*10^24 kg
m2 = 497 kg
r = 1.92 earth radii = 1.92 * (6378140 m) = 1.2246*10^7 m
Replacing all these values on the gravitational law, we get:
F = 1321.45 N
a) and b)
Both bodies will feel a force with the same magnitude 1321.45 N but directed in opposite directions.
The acceleration can be calculated dividing the force by the mass of the object
c)
a_satellite = F/m_satellite = ( 1321.45 N)/(497 kg)
a_satellite = 2.66 m/s^2
d)
a_earth = F/earth's mass = (1321.45 N)/( 5.9742*10^24 kg)
a_earth = 2.21*10^-22 m/s^2
Answer:
D. 1/9
Explanation:
Firstly, draw the circuits, then you solve for resistance in series with the formula- R1 + R2... And in parallel- 1/R1 + 1/R2...
Then after getting your resistance, use the formula for power that relates with resistance and voltage.
This the ratio will be 1/9. The parallel circuit has 1/9 the resistance of the series circuit. Since the potential difference across the two circuits is the same, this implies that the parallel circuit will give out 9 times more power than the series circuit.