A 1400 kg vehicle travelling at 22 m/s slows at a constant rate to 4.5 m/s in 6.75 s. What was the net force acting on the car d
1 answer:
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Explanation:
Given that,
A student travels 11 m north and then turns around to travel 25 m south.
Total time, t = 12 s
The total distance or the total path covered by the student is equal to 11 m + 25 m = 36 m
Displacement of the student or the shortest path covered is d = 25-11 = 14 m
(a) The student's average speed = total distance/total time
(b) The student's average velocity = total displacement/total time
Assuming constant acceleration due to gravity of , and assuming the passengers start at rest, so that
, we have
or 54 m/s if taking significant digits into account.