Extrusive rocks forms beneath earth's surface true or false

A 550N object has a coefficient of .012 against a smooth surface. What

Brrunno [24]

Vertically, the object is in equilibrium, so that the net force in this direction is

∑ F (vertical) = n - mg = 0

where n is the magnitude of the normal force due to the contact between the object and surface. You're given that the object's weight is mg = 550 N, so n = 550 N as well.

Horizontally, the net force would be

∑ F (horizontal) = p - f = 0

where p is the magnitude of the applied force and f is the magnitude of (kinetic) friction opposing p. Now,

f = 0.012n = 0.012 (550 N) = 6.6 N

so that you need to apply a force of p = 6.6 N to keep the object sliding at a steady pace.

4 0

3 years ago

Joshua skates in a straight line at a constant speed for 1 min, then begins going in circles at the same rate of speed, and fina

AlexFokin [52]

Answer:

When he begins going in circles at the same rate of speed

Explanation

When he begins going circles he speed begins to increase means he is accelerating

7 0

3 years ago

At the nose of a missile in flight, the pressure and temperature are 5.6 atm and 850°R, respectively. Calculate the density and

Contact [7]

To solve this problem we will apply the definition of the ideal gas equation, where we will clear the density variable. In turn, the specific volume is the inverse of the density, so once the first term has been completed, we will simply proceed to divide it by 1. According to the definition of 1 atmosphere, this is equivalent in the English system to

$1atm = 2116lb/ft^2$