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meriva
3 years ago
15

Extrusive rocks forms beneath earth's surface true or false

Physics
1 answer:
Verizon [17]3 years ago
8 0
The answer is false your welcome
You might be interested in
as an aid in understanding this problem. The drawing shows a positively charged particle entering a 0.61-T magnetic field. The p
miv72 [106K]

Answer:

E = 420.9 N/C

Explanation:

According to the given condition:

Net\ Force = 2(Magnetic\ Force)\\Electric\ Force - Magnetic\ Force = 2(Magnetic\ Force)\\Electric\ Force = 3(Magnetic\ Force)\\qE = 3qvBSin\theta\\E = 3vBSin\theta

where,

E = Magnitude of Electric Field = ?

v = speed of charge = 230 m/s

B = Magnitude of Magnetic Field = 0.61 T

θ = Angle between speed and magnetic field = 90°

Therefore,

E = (3)(230\ m/s)(0.61\ T)Sin90^o

<u>E = 420.9 N/C</u>

3 0
3 years ago
A cylinder of radius R and height H is floating upright in
emmainna [20.7K]

Answer:

Pressure difference between Top and Bottom of the cylinder is given as

\Delta P = \frac{gH}{2}(\rho_A + \rho_B)

Explanation:

As we know that the force due to pressure is balanced by the weight of the cylinder

So we will have

F = mg

so we have

\Delta P \pi R^2 = mg

so we have

\Delta P \pi R^2 = \pi R^2(\rho_A(\frac{H}{2}) + \rho_B(\frac{H}{2}))g

so we have

\Delta P = \frac{gH}{2}(\rho_A + \rho_B)

6 0
3 years ago
What feature on the periodic table separates the metals and non metals?
sertanlavr [38]
Answer: the amphoteric line, mental- nonmetal line, metalloid line, staircase, semimetal line. it can be called any of these names
7 0
3 years ago
What is at the center of a black hole
mafiozo [28]
The center of the ghole is the singularity. or a point where extremely large amounts of matter are crushed into an infinitely small amount of space. hope it helps :)
6 0
3 years ago
What is the wave length if the distance from the central bright region to the sixth dark fringe is 1.9 cm . Answer in units of n
Yuri [45]

Complete Question

The complete question is shown on the first uploaded image  

Answer:

The  wavelength is  \lambda  =  622 nm

Explanation:

  From the question we are told that

    The distance of the slit to the screen is  D  = 5 \ m

    The order of the fringe is m  =  6

     The distance between the slit is  d = 0.9 \ mm  =  0.9 *10^{-3} \ m

    The fringe distance is  Y =  1.9 \ cm  =  0.019 \ m

Generally the for a dark fringe the fringe distance is  mathematically represented as

        Y  = \frac{[2m  - 1 ] *  \lambda *  D  }{2d}

=>     \lambda  =  \frac{Y *  2 *  d }{[2*m  -  1] *  D}

substituting values

=>      \lambda  =  \frac{0.019 *  2 *  0.9*10^{-3} }{[2*6  -  1] *  5}

=>     \lambda  =  6.22 *10^{-7} \ m

       \lambda  =  622 nm

8 0
2 years ago
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