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lbvjy [14]
3 years ago
6

How many mercury atoms are there in 3.8 mol of mercury? Show work please

Chemistry
1 answer:
netineya [11]3 years ago
4 0
There are 6.02x10^22 molecules of any atom/molecule in one mole of anything.

Therefore no. of atoms in 3.8 mols of Mercury= 3.8 * 6.02x10^22=  2.2876x10^23 atoms
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Chlorine is used to disinfect swimming pools. the accepted concentration for this purpose is 1.00 ppm chlorine, or 1.00 g of chl
frez [133]

The accepted concentration of chlorine is 1.00 ppm that is 1 gram of chlorine per million of water.

The volume of water is 2.29\times 10^{4} gal.

Since, 1 gal= 3785.41 mL

Thus, 2.29\times 10^{4} gal=2.29\times 10^{4}\times 3785.41 mL=8.66\times 10^{7}mL

Density of water is 1 g/mL thus, mass of water will be 8.66\times 10^{7}g.

Since, 1 grams of chlorine →10^{6} grams of water.

1 g of water →10^{-6} g of chlorine and,

8.66\times 10^{7}g of water →86.6 g of chlorine

Since, the solution is 9% chlorine by mass, the volume of solution will be:

V=\frac{100}{9}\times 86.6 mL=9.62\times 10^{2} mL

Thus, volume of chlorine solution is 9.62\times 10^{2} mL.

6 0
3 years ago
Please help me answser this, its a photo<br><br>o element<br>o subscribe<br>o coefficient
Oliga [24]

Answer:

3 atoms of (C)carbon, 5 atoms of (H)hydrogen and 2 atoms of (O)oxygen

Explanation:

i don't know what you mean by subscribe

and i don't know what a coefficient is

4 0
3 years ago
what mass of sodium fluoride (FW=42.0 g/mol) must be added to 3.50 x 10^2 mL of water to give a solution with pH = 8.40?
MaRussiya [10]

Answer:

Explanation:

Sodium fluoride, being a salt, dissolves in water completely producing F ⁻ ions. Now  F⁻ is the conjugate base of the weak acid HF, so in water we will have the following equilibrium:

F⁻  +  H₂O ⇆ HF + OH⁻

Given this equilibrium, we need to calculate Kb from the Ka for HF,  the [ OH ⁻] from the given pH, and finally the mass needed to produce that  OH⁻ concentration.  

The equilibrium constant, Kb , can be calculated from Kw = Ka x Kb, where Kw = 10⁻¹⁴ and Ka for HF is  6.6 x 10⁻⁴ from reference tables.

Kb = 10⁻¹⁴ / 6.6 x 10⁻⁴ = 1.5 x 10⁻¹¹

pH + pOH = 14  ⇒ pOH = 14 - 8.40 = 5.60

[ OH⁻ ] = 10^-5.60 = 2.51 x 10⁻⁶

Now we have all the information :

                                   F⁻                    HF                        OH⁻

Equilibrium                 X                  2.51 x 10⁻⁶            2.51 x 10⁻⁶

(2.51 x 10⁻⁶)² / X  =  1.5 x 10⁻¹¹     ⇒  X =  (2.51 x 10⁻⁶)²  / 1.5 x 10⁻¹¹

X = [ F⁻ ] = 0.41 M

For 350 mL ( 0.35 L ) we need to add:

0.41 mol HF/ 1 L  *  0.35 L = 0.144 mol

and finally the mass will be:

0.144 mol NaF *  42.0 g/mol NaF = 6.03 g NaF

7 0
3 years ago
An order is given to administer 57 g of lactulose syrup, often used for treating complications of liver disease. The suspension
Angelina_Jolie [31]

Answer : The volume given to the patient should be, 85.5 mL

Explanation :

As we are given that the suspension contains 10g/15mL.

Now we have to determine the volume should be given to the patient.

As, 10 grams of lactulose syrup needed 15 mL volume of solution

So, 57 grams of lactulose syrup needed \frac{57g}{10g}\times 15mL=85.5mL volume of solution

Thus, the volume given to the patient should be, 85.5 mL

8 0
3 years ago
Identify which one of the three methods of analysis (i.e., TLC, IR and melting point) provides information about the structure o
Alex787 [66]

Answer:

IR provides structural information about a molecule. TLC and melting point analysis do not provide structural information.

Explanation:

IR gives information about the functional groups present in a molecule. The vibrational frequency of each functional group gives information about the structure of the entire molecule.

Structural features of a molecule are deduced by matching the vibrational frequencies of  groups obtained from the IR spectroscopy with that of known functional groups in literature.

Melting point is a qualitative method that can only yield information about the identity of a compound and not its structure. Each compound has its unique melting point recorded in literature and any pure sample of the same compound must have the same sharp meting point.

Thin-layer chromatography (TLC) is a chromatography technique used to separate non-volatile mixtures. After separating the components of the mixture, it does not give any information regarding the identity or the structure  of the components of the mixture.

Therefore, only IR yields structural information about a sample.

6 0
2 years ago
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