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Answer:
d = 8 g/mL
Explanation:
Given data:
Mass of metal = 24 g
Volume of eater = 45 mL
Volume of water + metal = 48 mL
Density of iron metal = ?
Solution:
Volume of metal:
Volume of metal = volume of water+ metal - volume of water
Volume of metal = 48 mL - 45 mL
Volume of metal = 3 mL
Density of metal:
d = m/v
d = 24 g/ 3 mL
d = 8 g/mL
to neutralize 1 mole of H2 S o4 we need one mole of any if we are having 50 grams of H2 S o4 it means the mole of H2 S o4 in 50 gram will be 50×40)/98 hence
utilising 50 grams of H2 S o4 we need approximately 20. 5 gm of Naoh
