This is most definitely a physiological hazard
Answer:
Explanation:
The time period of the pendulum containing simple pendulum is given by

where, L is the length of the pendulum and g is the value of acceleration due to gravity.
The time period of the clock using the spring mechanism is given by

where, m is the mass of the block attached to the spring and k is the spring constant.
here we observe the time period of the pendulum depends on the value of acceleration due to gravity. The value of acceleration due to gravity decreases as we go on the heights that means when the clock is taken to the mountain, the value of g decreases and thus, the value of time period increases and the clock runs slow.
So, the clock containing the spring system gives the accurate reading rather than the clock containing simple pendulum.
r = 30m
v = 2.5 m/s
m = .02kg
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v = r*omega
omega = (delta thaeda)/(delta time)
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2.5 m/s = 30m*omega
.08333... = omega
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*note, omega stands for angular velocity
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Also, it's been a while since I've done a physics problem like this so I could be wrong. I think this is the answer though :)