Answer:
hello your question has some missing values attached below is the complete question with the missing values
answer :
a) 0.083 secs
b) 0.33 secs
c) 3e^-4/3
Explanation:
Given that
g = 32 ft/s^2 , spring constant ( k ) = 2 Ib/ft
initial displacement = 1 ft above equilibrium
mass = weight / g = 4/32 = 1/8
damping force = instanteous velocity hence β = 1
a<u>)Calculate the time at which the mass passes through the equilibrium position.</u>
time mass passes through equilibrium = 1/12 seconds = 0.083
<u>b) Calculate the time at which the mass attains its extreme displacement </u>
time when mass attains extreme displacement = 1/3 seconds = 0.33 secs
<u>c) What is the position of the mass at this instant</u>
position = 3e^-4/3
attached below is the detailed solution to the given problem
Answer
given,
mass of baseball(m) = 144 g = 0.144 Kg
initial velocity(u) = 29 m/s
mass of brick(M) = 5.25 Kg
speed of the brick (v') = 1.32
speed of base ball after collision = ?
using conservation of momentum
m u = m v + Mv'
0.144 x 29 = 0.144 v + 5.25 x 1.32
0.144 v = -2.754
v = -19.125 m/s
b) KE before collision
KE_i = 60.55 J
KE after collision
KE_f = 30.91 J
I think the correct answer is A mark has greater gravitational potential energy
:)
Answer:
0.68 s
Explanation:
We are given that
Initial velocity of box=
Final velocity of box=v=11.5 m/s
Distance=d=8.5 m
We have to find the time taken by box to slow by this amount.
We know that
Substitute the values
We know that
Acceleration=
Substitute the values
Hence, the time taken by box to slow by this amount=0.68 s