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dimaraw [331]
3 years ago
5

What is the displacement of the object?

Physics
1 answer:
sveta [45]3 years ago
6 0

Answer:

Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

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In t-ball, young players use a bat to hit a stationary ball off a stand. The 140 g ball has about the same mass as a baseball, b
Talja [164]

Answer:

a) a_{ball} = 6000\,\frac{m}{s^{2}}, b) F = 840\,N

Explanation:

a) The physical system for the ball is modelled after the Impulse Theorem. The Impulse to accelerate the ball is:

Imp =m_{ball}\cdot v_{f}

Imp = (0.14\,kg)\cdot (12\,\frac{m}{s})\\Imp = 1.68\,N\cdot s

The acceleration of the ball is derived as follows:

a_{ball}=\frac{Imp}{m_{ball}\cdot\Delta t}

a_{ball} = \frac{1.68\,N\cdot s}{(0.14\,kg)\cdot(2\times 10^{-3}\,s)}

a_{ball} = 6000\,\frac{m}{s^{2}}

b) The net forced is obtained by the use of the concept of force for a system with a constant mass:

F = (0.14\,kg)\cdot(6000\,\frac{m}{s^{2}} )

F = 840\,N

5 0
3 years ago
Which of the following statements would NOT result in an eclipse? a. The Earth is positioned directly between the Sun and the Mo
vovangra [49]

c. The Moon is positioned directly between the earth and the sun is the statement that does not result in an eclipse.

Explanation:

  • The Sun is completely blocked in a solar eclipse because the Moon passes between Earth and the Sun.
  • it is just the right distance away from Earth, the Moon can fully blocks the Sun's light from Earth's perspective
3 0
4 years ago
Cual es la energía cinética de un objeto cuya masa es de 2kg y se mueve a una velocidad de 5 m/s2 * a)10 J b)25 J c)50J d)98J
Advocard [28]
Let the mass be m
v = 5m/s
K.E = 25 J
K.E = 1/2 mv^2
25 = 1/2 m (5)^2
25 x 2 = 25m
m = 2 kg
Now if the velocity becomes 3 times then the velocity is 3 x 5 = 15m/S
Now new K.E = 1/2 x 2 x 15^2
= 225 J
7 0
3 years ago
What is the wavelength of a wave?
PIT_PIT [208]
I know for a fact the answer is D. the distance traveled by the wave during one full cycle
6 0
3 years ago
Read 2 more answers
A 3-ton Toyota land cruiser travelled at a speed of 45m/s, collides with a 2- ton comfort taxi which was parked in front of the
Olin [163]

Answer:

v = 27 m/s

Explanation:

To find the speed of cars after the collision  you take into account the momentum conservation law. Total momentum of both cars before the collision must be equal to the total momentum of both cars after the collision.

After the collision both cars traveled together, then you have:

m_1v_1+m_2v_2=(m_1+m_2)v   (1)

m1: mass of the Toyota = 3-ton = 3000 kg

m2: mass of the taxi = 2-ton = 2000kg

v1: speed of the Toyota before the collision = 45m/s

v2: speed of the car before the collision = 0 m/s (it is  at rest)

v: speed of both cars after the collision = ?

You solve the equation (1) for v:

v=\frac{m_1v_1+m_2v_2}{m_1+m_2}

Next, you replace the values of the rest of the variables:

v=\frac{(3000kg)(45m/s)+0kgm/s}{3000kg+2000kg}=27\frac{m}{s}

hence, just after the collision both cars have a speed of 27m/s

7 0
3 years ago
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