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Reil [10]
3 years ago
6

Please select the word from the list that best fits the definition Fossils up to 75,000 years old can be dated with ______.

Physics
2 answers:
mash [69]3 years ago
5 0

Hello Paige,

Question - Please select the word from the list that best fits the definition Fossils up to 75,000 years old can be dated with ______.

Answer - Carbon 14

garri49 [273]3 years ago
4 0

Fossils up to 75,000 years old can be dated with Carbon-14.

Carbon-14 is effective in carbon-dating is used to date ancient fossils. The closer the age to the present, the more accurate the dating would be.

hope this helps

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A copper Wire has a length of 160 m,and a diameter of 1.0 mm,if ,the wire is connected to a 1.5-Volt battery ,How much Current f
makkiz [27]
Some guidance notes which may help.To calculate the current flow, Ohm's law can be used. This can be written as current=voltage/resistance, or I=V/R. V is 1.5V.R for the copper wire quoted would be calculated as R = resistivity x length/cross sectional area. The area would be calculated from the formula area = pi x diameter squared/4So, R=resistivity x length divided by (pi x diameter squared/4)Until is the resistivity of copper is known, that's about as far as can be gone.Any further questions, please ask.
3 0
4 years ago
Problem: A lossless 50-Ω transmission line is terminated in a load with ZL = (50 + j25) Ω. Use the Smith chart to find the follo
Nadya [2.5K]

Answer:  (a). ΓL = 0.246 < 75°

(b). S =  1.7

(c). Zin =  (30-j)λ

(d). jreal = Arc Po = 0.105λ

(e). jmax = jreal = 0.105λ

Explanation:

attached is a document to help in understanding.

So we will begin with a step by step analysis of the problem.

from the diagram we have that  ZL = (50 + j25) Ω.

where ZL = ZL / Z₀ = 50 + j25 / 50 = 1 + j0.5

so we mark this on the chart as point 'P'

(a) ΓL = mP/m 'P' < Θ L = 1.7/6.9 < 75°

        ΓL = 0.246 < 75°

(b) This s-circle 's' is given thus s = r = 1.7 on the RHS of the chart

       S =  1.7

(c) we are to calculate the input impedance;

ζin = Q = 0.6 - j0.02

therefore Zin = Z₀ζin = 50(0.6 - j0.02) = (30-j)λ

Zin = (30-j)λ

(d) here we are taking R as the diameter opposite of Q on the s=circle

   so R = γin = 1.7 + j0.02

         yin = yo (γin) = (1.7+j0.02) / 50 = (34 + j0.4)ms

          yin = (34 + j0.4)ms

(e) move from 'p' on s-circle to 'o'

where maximum impedance = Znxl = Zos

which gives jreal =  Arc Po = 0.105λ

(f) jmax = jreal = 0.105λ

cheers i hope this helps

3 0
3 years ago
What evidence can you cite to support the claim that the frequency of light does not change upon reflection?
soldier1979 [14.2K]

Answer: The color of an image is equal to the color of the item forming the picture. When you have a take a observe your self in a mirror, the color of your eyes would not alternate. The reality that the color is equal is proof that the frequency of light would not alternate upon reflection.

8 0
4 years ago
I have 6 questions from newtons first law,<br> Second law and third law topic.
iogann1982 [59]
Rolling friction is less than sliding friction

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3 years ago
When the northern hemisphere is tilted toward the sun that part of the earth is closer to the sun and thus hotter? True or false
Ratling [72]

<u>False</u>

<u>Explanation:</u>

Most of us have a belief that Earth is very close to the sun in summer season and so it is hotter. Also, since Earth is far away from the sun in winter season, it is colder.  Though this idea looks true, it is incorrect.

The orbit of the Earth isn't a perfect circle. It is quite tilted. During some months of the year, Earth is very close to the sun than at other times. We have winter when the Earth is very close to the sun and summer when it is far away in the Northern Hemisphere. So when we compare the distance of the Sun from the Earth, this change in Earth's distance throughout the year does not affect our weather much.

8 0
3 years ago
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