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svlad2 [7]
3 years ago
10

A force that is doing work on a ball when that ball is falling through the air.

Physics
1 answer:
Ronch [10]3 years ago
3 0

Answer:

i think the answer is gravity

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Fatima is watching her pet cat, Winter, napping in the sun. Fatima is curious about the heart rate of Winter when she is napping
svetoff [14.1K]

Answer:

Explanation:

There are two hypotheses she could test:

A cat's heart rate changes while it is napping.

A cat's heart rate does not change while it is napping.

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4 years ago
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Which piece of evidence did Alfred Wegener use to develop the theory of continental drift?
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The right answer for the question that is being asked and shown above is that: "A.tectonic activity concentrated in certain areas." A piece of evidence did Alfred Wegener use to develop the theory of continental drift is that <span>A.tectonic activity concentrated in certain areas</span>
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3 years ago
Often called velocity this is the velocity of an object at a particular moment in time
Yuliya22 [10]
Instantaneous speed?
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3 years ago
"Light traveling in a medium with a refractive index 1.11 is incident on a plate of another medium with index of refraction 1.66
Kamila [148]

Answer:

56°

Explanation:

Brewsters angle can be simply derived from

n1sin theta1= n2sintheta2= n2costheta1

because the reflected light will be 100% polarized if it is reflected at an angle 90o to the refracted light. Hence, Brewsters angle is

Tan theta= n2/n1

1.66/1.11= 1.495

Theta = 56°

Explanation:

7 0
4 years ago
A hockey puck is hit on a frozen lake and starts moving with a speed of 12.0 m/s. exactly 5.0 s later, its speed is 6.0 m/s. wha
Anna35 [415]
1) In an uniformly accelerated motion, the acceleration is given by:
a= \frac{v_f-v_i}{\Delta t}
where v_f is the final speed, v_i is the initial speed, and \Delta t is the time interval between the initial and final point of the motion.

Using the data of the problem: v_i = 12.0 m/s, v_f = 6.0 m/s, and the time \Delta t = 5.0 s, the acceleration is
a= \frac{6 m/s-12 m/s}{5.0 s}=-1.2 m/s^2
where the negative sign means that the hockey puck is decelerating.

2) The frictional force F between the puck and ice is responsible for the deceleration of the puck, and for second Newton's law this force is equal to the product between the mass of the puck m and the acceleration:
F=ma (1)
The frictional force can also be written as
F=-\mu_D mg (2)
where \mu_D is the coefficient of kinetic friction, and where the negative sign is due to the fact that the frictional force acts against the direction of motion of the puck. By equilizing (1) and (2) we can find the value of this coefficient:
ma=-\mu_D mg
\mu_D =   -\frac{a}{g}=  -\frac{-1.2 m/s^2}{9.81 m/s^2}=0.12
5 0
4 years ago
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