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2 years ago

6

What do our ears do

2 answers:

Gnesinka [82]2 years ago

8 0

Answer;

Hear

Explanation:

Your ears do the remarkable job of allowing you to hear a huge range of sounds, from a whisper to a loud bang. To do this, the ear transforms sound energy into electrical signals which the brain can interpret. Your ears also help to maintain your balance.

Can I get brainliest

andre [41]2 years ago

7 0

Answer:

hear

Explanation:

stuff stuff moaning and stuff

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Science: Could a dysfunction or disease of the nervous system affect other body systems, such as the muscular or digestive syste

SashulF [63]

Answer:

You may experience the sudden onset of one or more symptoms, such as: Numbness, tingling, weakness, or inability to move a part or all of one side of the body (paralysis). Dimness, blurring, double vision, or loss of vision in one or both eyes. Loss of speech, trouble talking, or trouble understanding speech.

Request: Please mark me as the brainliest.

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2 years ago

What would be the diameter of the earth if it had the density of a neurton star

Marat540 [252]

The entire mass of the Earth at neutron star density would fit into a sphere of 305 m in diameter

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2 years ago

A truck carrying a 65.4-kg crate accelerates from rest to [07]____________________ km/hr on a flat horizontal surface in 15.2 se

NikAS [45]

Answer:

The work done on the crate by the truck is 9472.54 J.

Explanation:

Given that,

Mass of the truck, m = 65.4 kg

Initially, the object is at rest, u = 0

Final speed of the truck, v = 61.3 km /h = 17.02 m/s

m/s

Time, t = 15.2 s

We need to find the work done on the crate by the truck. The work done is equal to the change in kinetic energy of the truck as :

$W=\Delta K$

$W=K_f-K_i$

$W=K_f-0$

$W=\dfrac{1}{2}mv^2$

$W=\dfrac{1}{2}\times 65.4\times (17.02)^2$

$W=9472.54\ J$

So, the work done on the crate by the truck is 9472.54 J. Hence, this is the required solution.

8 0

3 years ago

How much kinetic energy does a 7.2-kg dog need to make a vertical jump of 1.2 m? the acceleration due to gravity is 9.8m / s^2

Roman55 [17]

$E_k=mgh\\\\m=7.2\ kg\\\\g=9.8\ m/s^2\\\\h=1.2\ m\\\\E_k=7.2\cdot9.8\cdot1.2=84.672\ \left[\frac{kgm^2}{s^2}\right]=84.672\ [J]$

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2 years ago

Read 2 more answers

An object's distance from a converging lens is 3.78 times the focal length. a) Determine the location of the image. Express the

Romashka-Z-Leto [24]

Answer:

a) v=1.36f

b)m=.36

c) real

d) Inverted

Explanation:

a)

In this question we have given,

object distance from converging lens,u=-3.78f

focal length of converging lens,=f

we have to find location of image,v=?

and magnification,m=?

we know that u, v and f are related by following formula

$\frac{1}{f} =\frac{1}{v}- \frac{1}{u}$ .............(1)

put values of f u in equation (1)

we got,

$\frac{1}{f} =\frac{1}{v}- \frac{1}{-3.78f}$

$\frac{1}{f}-\frac{1}{3.78f} =\frac{1}{v}$

$\frac{2.78}{3.78f} =\frac{1}{v}$

or

v=1.36f

b) Magnification, $m=\frac{v}{u} \\m=\frac{1.36f}{3.78f}\\m=.36$

c)

Here the object is located further away from the lens than the focal point therefore image is real image and inverted.

d) image is inverted

7 0

3 years ago