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Anit [1.1K]
3 years ago
6

What do our ears do​

Physics
2 answers:
Gnesinka [82]3 years ago
8 0
Answer;

Hear

Explanation:

Your ears do the remarkable job of allowing you to hear a huge range of sounds, from a whisper to a loud bang. To do this, the ear transforms sound energy into electrical signals which the brain can interpret. Your ears also help to maintain your balance.

Can I get brainliest

andre [41]3 years ago
7 0

Answer:

hear

Explanation:

stuff stuff moaning and stuff

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A rock rolls down a hill. Which form of energy is this an example of? (2 points)
Bond [772]

Answer:

c.Mechanical

Explanation:

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Sics and Chemistry A (2nd Six Weeks) - SC3200SFA/01
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Force = Mass * Acceleration therefore the red ball with the higher mass will have more force and greater acceleration
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A bowling ball with a mass of 9kg is thrown down a lane with a constant speed of 3 m/s. The ball hits the 1.5kg pin, initially a
olasank [31]

Answer:

M1 V1 = M1 V2 + M2 V3    conservation of momentum

V2 = (M1 V1 - M2 V3) / M1      where V2 = speed of M1 after impact

V2 = (3 * 9 - 1.5 * 5) / 9  =   (27 - 7.5) / 9 = 2.17 m/s

Note: All speeds are in the same direction and have the same sign

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2 years ago
Provide one example of how Science drives Technology.
evablogger [386]

Answer:

Scientific knowledge is used to create new technologies. New technologies often allow scientists to explore nature in different ways and make new discoveries.

Explanation:

7 0
3 years ago
Read 2 more answers
A piece of aluminum has a volume of 1.50 10-3 m3. the coefficient of volume expansion for aluminum is β = 69 ✕ 10-6 (°c)-1. the
Alex17521 [72]

Answer:

W = 3.12 J

Explanation:

Given the volume is 1.50*10^-3  m^3 and the coefficient of volume for aluminum is β = 69*10^-6 (°C)^-1. The temperature rises from 22°C to 320°C. The difference in temperature is 320 - 22 = 298°C, so ΔT = 298°C. To reiterate our known values we have:

β = 69*10^-6 (°C)^-1       V = 1.50*10^-3  m^3       ΔT = 298°C

So we can plug into the thermal expansion equation to find ΔV which is how much the volume expanded (I'll use d instead of Δ because of format):

dV = \beta V_{0} dT\\dV = (69*10^{-6})( C)^{-1} * (1.50*10^{-3})m^{3} * (298)C\\dV = 3.0843*10^-5

So ΔV = 3.0843*10^-5 m^3

Now we have ΔV, next we have to solve for the work done by thermal expansion. The air pressure is 1.01 * 10^5 Pa

To get work, multiply the air pressure and the volume change.

W = P * dV = (1.01 * 10^5)Pa * (3.0843*10^{-5})m^3\\W = 3.115143J

W = 3.12 J

Hope this helps!

4 0
3 years ago
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