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3 years ago

If you have 5 moles of carbon dioxide at 30degrees C and under 600mmHg of pressure, what will the volume be

Chemistry

1 answer:

trapecia [35]3 years ago

7 0

Answer:

157.64 L

Explanation:

We'll begin by converting 30 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 30 °C

T(K) = 30 °C + 273

T (K) = 303 K

Next, we shall convert 600 mmHg to atm. This can be obtained as follow:

760 mmHg = 1 atm

Therefore,

600 mmHg = 600 mmHg × 1 atm / 760 mmHg

600 mmHg = 0.789 atm

Finally, we shall determine the volume of the gas. This can be obtained as follow:

Number of mole (n) = 5 moles

Temperature (T) = 303 K

Pressure (P) = 0.789 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =?

PV = nRT

0.789 × V = 5 × 0.0821 × 303

0.789 × V = 124.3815

Divide both side by 0.789

V = 124.3815 / 0.789

V = 157.64 L

Therefore, the volume of the gas is 157.64 L

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2 years ago

A sample of 0.0860 g of sodium chloride is added to 30.0 mL of 0.050 M silver nitrate, resulting in the formation of a precipita

mestny [16]

Answer:

The answer is:

(a) $NaCl(aq)+AgNO_3(aq) \rightarrow AgCl(r) +NaNO_3 (aq)$

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Explanation:

Given:

The mass of NaCl,

= 0.0860 g

The molar mass of NaCl,

= 58.44 g/mol

The volume of $AgNO_3$ ,

= 30.0 ml

or,

= 0.030 L

Molarity of $AgNO_3$ ,

= 0.050 M

Moles of NaCl will be:

= $\frac{Given \ mass}{Molar \ mass}$

= $\frac{0.0860}{58.44}$

= $0.00147 \ mol$

now,

Moles of $AgNO_3$ will be:

$= Molarity\times Volume$

$= 0.050\times 0.030$

$=0.0015 \ mol$

(a)

The reaction is:

⇒ $NaCl(aq)+AgNO_3(aq) \rightarrow AgCl(r) +NaNO_3 (aq)$

(b)

1 mole of NaCl react with,

= 1 mol of $AgNO_3$

0.0015 mol $AgNO_3$ needs,

= $0.00150 \ mol \ NaCl$

Available mol of NaCl < needed amount of NaCl

So,

The limiting reagent is "NaCl".

(c)

The precipitate formed,

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= $0.211 \ g \ AgCl$

4 0

3 years ago

1. Define the units for molarity. Page |152 Exp. 14 pH and Solutions Pre Lab Questions (1 of 1) 2. A solution contains 5.25 gram

Ne4ueva [31]

Answer:

1. mol/L

2. 0.120 M

Explanation:

1. Molarity is equal to the moles of solute divided by the liters of solution. The units of molarity are mol/L.

Step 1: Given data

Mass of sodium chloride (solute): 5.25 g

Volume of solution (V): 750.0 mL = 0.7500 L

Step 2: Calculate the moles of solute (n)

The molar mass of NaCl is 58.44 g/mol.

n = 5.25 g × 1 mol/58.44 g = 0.0898 mol

Step 3: Determine the molarity of the solution

We will use the definition of molarity

M = n/V

M = 0.0898 mol / 0.7500 L = 0.120 M

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3 years ago

The standard unit for measuring volume is the _____.

Otrada [13]

The answer is B I hope this helps you

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3 years ago