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r-ruslan [8.4K]
3 years ago
5

The table describes how some substances were formed.

Chemistry
2 answers:
NeX [460]3 years ago
8 0

Answer:

the answer is

Explanation:

Sugar and water make a homogeneous mixture (the same proportions of its components throughout any given sample).

lisabon 2012 [21]3 years ago
6 0

Explanation:

Which is a pure substance?

1. soda

2. gasoline

3. salt water

4. carbon dioxide

carbon dioxide

Bromine, a liquid at room temperature, has a boiling point of 58°C and a melting point of -7.2°C. Bromine can be classified as a

1. compound.

2. impure substance.

3. mixture.

4. pure substance.

pure substance.

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What can be deduced from the fact that a substance has a pH of 7?
balandron [24]

Answer:

A.

Explanation:

A) The number of H+ ions in the substance is equal to the number of OH-ions.

8 0
3 years ago
A student is trying to identify a clear liquid that he finds in a beaker in the classroom. He thinks the liquid might be either
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Simply mulitply the volume by the density. As we shall see, this is dimensionally consistent.

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3 0
3 years ago
What is the percent composition of each element within the compound​
kogti [31]

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The percentage composition of a given compound is defined as <u>the ratio of the amount of each element to the total amount of individual elements present in the compound multiplied by 100. </u>Here, the quantity is measured in terms of grams of the elements present.

please give me brainliest

6 0
2 years ago
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Consider the reaction: N2(g) 2 O2(g)N2O4(g) Write the equilibrium constant for this reaction in terms of the equilibrium constan
Valentin [98]

Answer : The equilibrium constant for this reaction is, K=\frac{(K_b)^2}{K_a}

Explanation :

The given main chemical reaction is:

N_2(g)+2O_2(g)\rightarrow N_2O_4(g);  K

The intermediate reactions are:

(1) N_2O_4(g)\rightarrow 2NO_2(g);  K_a

(2) \frac{1}{2}N_2(g)+O_2(g)\rightarrow NO_2(g);  K_b

We are reversing reaction 1 and multiplying reaction 2 by 2 and then adding both reaction, we get:

(1) 2NO_2(g)\rightarrow N_2O_4(g);  \frac{1}{K_a}

(2) N_2(g)+2O_2(g)\rightarrow 2NO_2(g);  (K_b)^2

Thus, the equilibrium constant for this reaction will be:

K=\frac{1}{K_a}\times (K_b)^2

K=\frac{(K_b)^2}{K_a}

Thus, the equilibrium constant for this reaction is, K=\frac{(K_b)^2}{K_a}

5 0
3 years ago
Oxygen has 8 plus-charged protons. The number of minus-charged electrons is
DiKsa [7]

A single oxygen has atomic number 8 that means the nuclei of all oxygen atoms have eight protons. The number of minus-charged electron is two but the number of electrons is 10. <span>To gain a minus two-charge ion, it must have two more negative electrons than positive charged protons. With this, the ion has 10 electrons, which give it a -2 net charge. </span>

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