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shusha [124]
3 years ago
11

the bonding of two amino acids to form a larger molecule requires the addition of nitrogen the release of carbon dioxide the rel

ease of a water molecule the addition of a water molecule
Chemistry
1 answer:
Ksivusya [100]3 years ago
3 0
What is the question here?

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A small sack of sand has a density of 1.5 g/cm3 and a mass of 1500 g. How much space (volume) does the sand occupy?
d1i1m1o1n [39]
The answer would be 1000 cm3
8 0
3 years ago
Read 2 more answers
How many liters of hydrogen gas will be produced at STP from the reaction of 7.179 x 1023 atoms of magnesium with 54.21 g of pho
wlad13 [49]
<h3>Answer:</h3>

18.58 liters of hydrogen gas

<h3>Explanation:</h3>

We are given;

  • The equation;

3Mg + 2H₃(PO₄) → Mg₃(PO₄)₂ + 3H₂

  • Atoms of Magnesium = 7.179 x 10^23 atoms
  • Mass of phosphoric acid as 54.21 g

We are required to determine the volume of hydrogen gas produced;

Step 1; moles of Magnesium

1 mole of an element contains 6.02 × 10^23 atoms

therefore;

Moles of Mg = (7.179 x 10^23 ) ÷ (6.02 × 10^23)

                   = 1.193 moles

Step 2: Moles of phosphoric acid

moles = Mass ÷ Molar mass

Molar mass of phosphoric acid = 97.994 g/mol

Therefore;

Moles of Phosphoric acid = 54.21 g ÷ 97.994 g/mol

                                           = 0.553 moles

Step 3: Determine the rate limiting reagent

From the mole ratio of Mg to Phosphoric acid (3 : 2);

1.193 moles of magnesium requires 0.795 moles of phosphoric acid while,

0.0553 moles of phosphoric acid requires 0.8295 moles of Mg

Therefore, phosphoric acid is the rate limiting reagent

step 4: Determine the moles of hydrogen produced

From the equation, w moles of phosphoric acid reacts to produce 3 moles of hydrogen;

Therefore; moles of Hydrogen = moles of phosphoric acid × 3/2

                                                   = 0.553 moles × 3/2

                                                   = 0.8295 moles

Step 5: Volume of hydrogen gas

1 mole of a gas occupies a volume of 22.4 liters at STP

Therefore;

Volume of Hydrogen = 0.8295 moles × 22.4 L/mol

                                  = 18.58 Liters

Therefore; 18.58 liters of hydrogen gas  will be produced

4 0
3 years ago
40 Points Need help ASAP
Sveta_85 [38]
It requires a force in the direction opposite to the motion of the object for it to slow down.
3 0
3 years ago
Question 2*
Paraphin [41]

Answer:

Sc(OH)₃ = 96 g/mol

Explanation:

Gram formula mass:

Gram formula mass is the atomic mass of one mole of any substance.

It can be calculated by adding the mass of each atoms present in substance.

Sc(OH)₃:

Atomic mass of Sc = 45 amu

Atomic mas of O = 16 amu

There are three atoms of O = 16 ×3

Atomic mas of H = 1 amu

There are three atoms of H = 1 ×3

Gram formula mass of Sc(OH)₃:

Sc(OH)₃ = 45 ×1 + 16 ×3 + 1  ×3

Sc(OH)₃ = 96 g/mol

6 0
3 years ago
What mass of natural gas (CH4) must you burn to emit 264 kJ of heat?
mariarad [96]
The heat released by cpmolete the combustion of organic products with oxygen is called heat of combustion.

Here 1 mol of CH4 realesed 802.3 KJ

To emit 264 kJ you multiply you need (1 mol of CH4/802.3 kJ)* 264 kJ = 0.329 mol of CH4

The molar mass, MM, of CH4 is 12 g/mol + 4*1g/mol = 16 g/mol

The to obtain the mass multiply the number of moles times the molar mass:

mass = n * MM = 0.329mol * 16g/mol = 5.26 grams

Answer: 5.26 grams



7 0
3 years ago
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