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Verizon [17]
3 years ago
12

You are playing hockey with friends on a very large frozen pond. The hockey puck is at your feet motionless. You take a slap-sho

t with your hockey stick and the hockey puck goes zooming off at a high rate of speed sliding along the ice. The hockey puck eventually comes to a stop because:
a. There is no net forward force on the puck and so it will eventually slow down.
b. Friction between the puck and the ice will do enough negative work on the puck to equal the positive work done by you on the puck.
c. Friction between the puck and the ice will do more negative work on the puck than you did positive work on the puck.
d. Friction between the puck and the ice will do less negative work on the puck than you did positive work on the puck.
Physics
1 answer:
lapo4ka [179]3 years ago
6 0

Answer:

The correct answer is letter b. Friction between the puck and the ice will do enough negative work on the puck to  equal the positive work done by you on the puck.

Explanation:

According to the Newton's First Law of Motion, the rocky puck would keep sliding on the ice forever. However, due to the friction acts on the puck, it will slow down and eventually stopping.  

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Answer:

The answer would be Igneous rock

Explanation:

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3 years ago
1. Determine the energy released per kilogram of fuel used.
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Calculate the energy in joules per kilogram of reactants given MeV per reaction. Energy is the ability or capacity to perform tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
Think of a mole of plutonium-239 (molar mass: 239 grams) as a mole of "reactions."

Energy used in the US per person annually = 3-5 X 1011
Population (number of people) = 3.108The required mass of the fuel is 3.5x1011 x3-1x10 8x 10)/6.703 X1013 kg. the mass required: 1.62 x 1033 kg Mev in Joules 6 is equal to 101.60*I0-
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8 0
2 years ago
El peso de María es de 617,4 N. Si en dos meses pierde 2,5 Kg de masa, ¿cuál será su nuevo peso?
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Two hundred and thirsty years
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4 years ago
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We push a 38.4-kg box across the floor at constant velocity. If we are pushing a horizontal force of 238 N, find the coefficient
zmey [24]

Answer: 0.62

Explanation:

Coefficient of friction is defined as the ratio of the moving force (Fm) acting on a body to the normal reaction (R).

Note that the normal reaction acts vertically on the object and is equal to the objects weight (W) i.e W=R

Since W = mg, W = 38.4 ×10

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Normal reaction = 384N

The horizontal force acting on the body will be the moving force which is 238N

Coefficient of friction = Fm/R

Coefficient of friction = 238/384

Coefficient of friction = 0.62

Therefore, coefficient of kinetic friction between the box and the floor is 0.62

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A racecar is equipped with a computer that records the reading on its speedometer every second during a race. If you graph this
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