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Verizon [17]
3 years ago
12

You are playing hockey with friends on a very large frozen pond. The hockey puck is at your feet motionless. You take a slap-sho

t with your hockey stick and the hockey puck goes zooming off at a high rate of speed sliding along the ice. The hockey puck eventually comes to a stop because:
a. There is no net forward force on the puck and so it will eventually slow down.
b. Friction between the puck and the ice will do enough negative work on the puck to equal the positive work done by you on the puck.
c. Friction between the puck and the ice will do more negative work on the puck than you did positive work on the puck.
d. Friction between the puck and the ice will do less negative work on the puck than you did positive work on the puck.
Physics
1 answer:
lapo4ka [179]3 years ago
6 0

Answer:

The correct answer is letter b. Friction between the puck and the ice will do enough negative work on the puck to  equal the positive work done by you on the puck.

Explanation:

According to the Newton's First Law of Motion, the rocky puck would keep sliding on the ice forever. However, due to the friction acts on the puck, it will slow down and eventually stopping.  

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Help with 5 and the question below. BRAINLIEST FOR THE CORRECT ANSWER! Urgent Physics help!
krok68 [10]

Sound level at distance of 15 m is given as 20 dB

so intensity at this distance is given as

L = 10 Log\frac{I}{I_0}

20 = 10 Log{I}{10^{-12}}

I_1 = 10^{-10}W/m^2

now if we move closer to some some distance the sound level is now 50 dB

now the intensity is given as

L = 10 Log\frac{I}{I_0}

50 = 10Log\frac{I}{10^{-12}}

I_2 = 10^{-7}W/m^2

now we know that

\frac{I_1}{I_2} = \frac{r_2^2}{r_1^2}

\frac{10^{-10}}{10^{-7}} = \frac{r_2^2}{15^2}

r_2 = 47 cm

so now the distance from friend must be 47 cm

8 0
2 years ago
Scientists are making plans to put a probe in orbit around Earth. They want the probe to enter the orbit shown below.
iris [78.8K]

An arrow which shows the direction that the probe should be moving in order for it to enter the orbit is X.

<h3>What is an orbit?</h3>

An orbit can be defined as the curved path through which a astronomical (celestial) object such as planet Earth, in space move around a Moon, Sun, planet or star.

In this scenario, if the scientists want the probe to enter the orbit they should ensure that probe moves in direction X. This ultimately implies that, the probe must move in the same direction as the orbit, in order to enter it.

Read more on orbit here: brainly.com/question/18496962

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6 0
2 years ago
Read 2 more answers
Which statements describe Earth? Select three options. It is an outer planet. It is a terrestrial planet. It was formed from gas
AVprozaik [17]

The formation of Earth is supported by the statements like, it is a terrestrial planet. it was formed from gas and dust. it was formed in a debris disk from colliding planetesimals.

The given problem is based on the correct statements entitling the description of Earth. Earth is amongst 8 planets in our solar system, that happen to orbit around the sun.

The statements given to describe the Earth are as follows:

  • Earth is not an Outer planet. It is an inner planet that lies closest to the sun after Mercury and Venus.
  • Earth is a terrestrial planet because it is having a compact and rocky surface. Also, it is known to be an as largest terrestrial planet in the solar system with extensive regions of liquids and water.
  • The abundant rocky surfaces have evolved from the cloud of dust and gas, during the post-Big Bang Era. So, it is somewhere true to say that Earth is formed from gas and dust.
  • The earlier atmosphere of Earth was known for having proportional layers of Hydrogen and Helium. Hence is quite true to say that the Earth is having an atmosphere of Hydrogen and helium gases, but it is not as thick as the like sun.
  • Majority of terrestrial planets are formed from the collision of planetesimals in a debris disk. With Earth being one of them, it is quite correct to consider the given statement.

Thus, we can conclude that the formation of Earth is supported by the statements like: it is a terrestrial planet, it was formed from gas and dust and it was formed in a debris disk from colliding planetesimals.

Learn more about the planet Earth here:

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3 0
2 years ago
A speedboat increases its speed from 14.5 m/s to 29.3 m/s in a distance of 172 m.
dalvyx [7]

Answer:

a. Acceleration, a = 1.88 m/s²

b. Time, t = 7.87 seconds.

Explanation:

Given the following data;

Initial velocity, U = 14.5m/s

Final velocity, V = 29.3m/s

Distance, S = 172m

a. To find the acceleration of the speedboat;

We would use the third equation of motion;

V² = U² + 2aS

Substituting into the formula

29.3² = 14.5² + 2a*172

858.49 = 210.25 + 344a

344a = 858.49 - 210.25

344a = 648.24

a = 648.24/344

Acceleration, a = 1.88 m/s²

b. To find the time;

We would use the first equation of motion;

V = U + at

29.3 = 14.5 + 1.88t

1.88t = 29.3 - 14.5

1.88t = 14.8

Time, t = 14.8/1.88

Time, t = 7.87 seconds.

6 0
3 years ago
A spherical shell is rolling without slipping at constant speed on a level floor. What percentage of the shell's total kinetic e
IgorC [24]

Answer:

41.667 per cent of the total kinetic energy is translational kinetic energy.

Explanation:

As the spherical shell is rolling without slipping at constant speed, the system can be considered as conservative due to the absence of non-conservative forces (i.e. drag, friction) and energy equation can be expressed only by the Principle of Energy Conservation, whose total energy is equal to the sum of rotational and translational kinetic energies. That is to say:

E = K_{t} + K_{r}

Where:

E - Total energy, measured in joules.

K_{r} - Rotational kinetic energy, measured in joules.

K_{t} - Translational kinetic energy, measured in joules.

The spherical shell can be considered as a rigid body, since there is no information of any deformation due to the motion. Then, rotational and translational components of kinetic energy are described by the following equations:

Rotational kinetic energy

K_{r} = \frac{1}{2}\cdot I_{g}\cdot \omega^{2}

Translational kinetic energy

K_{t} = \frac{1}{2}\cdot m \cdot R^{2}\cdot \omega^{2}

Where:

I_{g} - Moment of inertia of the spherical shell with respect to its center of mass, measured in kg\cdot m^{2}.

\omega - Angular speed of the spherical shell, measured in radians per second.

R - Radius of the spherical shell, measured in meters.

After replacing each component and simplifying algebraically, the total energy of the spherical shell is equal to:

E = \frac{1}{2}\cdot (I_{g} + m\cdot R^{2})\cdot \omega^{2}

In addition, the moment of inertia of a spherical shell is equal to:

I_{g} = \frac{2}{3}\cdot m\cdot R^{2}

Then, total energy is reduced to this expression:

E = \frac{5}{6}\cdot m \cdot R^{2}\cdot \omega^{2}

The fraction of the total kinetic energy that is translational in percentage is given by the following expression:

\%K_{t} = \frac{K_{t}}{E}\times 100\,\%

\%K_{t} = \frac{\frac{1}{2}\cdot m \cdot R^{2}\cdot \omega^{2} }{\frac{5}{6}\cdot m \cdot R^{2}\cdot \omega^{2} } \times 100\,\%

\%K_{t} = \frac{5}{12}\times 100\,\%

\%K_{t} = 41.667\,\%

41.667 per cent of the total kinetic energy is translational kinetic energy.

7 0
3 years ago
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