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fgiga [73]
3 years ago
9

Question 2 A horizontal line on a position vs time graph means the object is O moving faster. O at rest O slowing down. O moving

at a constant speed.​
Physics
1 answer:
Salsk061 [2.6K]3 years ago
5 0

Explanation:

this question can also shown in figure

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If Ike notices that there is a new moon tonight, when should he expect there to be a new moon again?
podryga [215]
Whatever phase of the moon Ike sees, he can expect to see
the same phase of moon again, after 29.53 days later.
5 0
3 years ago
Balance Ba(NO3)2 + Na2SO4 --> BaSO4 + NaNO3
Amiraneli [1.4K]
Ba(NO₃)₂  +  Na₂SO₄  → BaSO₄ + NaNO₃

By Trial and error.

Ba(NO₃)₂  +  Na₂SO₄  → BaSO₄ + 2NaNO₃

Check:

             LHS            RHS
Ba           1                1
N             2                2
S             1                1
O      3*2 + 4 = 10         4 + 2*3 = 10
8 0
3 years ago
Read 2 more answers
Red light has a longer wavelength and higher energy than blue light. True or False
Bingel [31]

Answer:

False

Explanation:

Visible light is composed of radiation of wavelengths between 400 and 700 nm. The sensitivity of the human eye depends on the wavelength and has a maximum at 550 nm. Some people are able to perceive from 380 to 780 nm.

The electromagnetic energy in a particular wavelength λ (in a vacuum) has an associated frequency f and a photonic energy E. Thus, the electromagnetic spectrum can be expressed in terms of any of these three variables, which are related by equations.

Thus, high frequency electromagnetic waves have a short wavelength and high energy; Low frequency waves have a long wavelength and low energy.

To calculate the energy of a photon the Planck formula is used is E = h · v, where E is the energy, h the Planck constant and v the frequency (Hz or s-1).  Where the frequency f is equal to the speed of the wave, divided by the wavelength λ .

That said we can say that it is false because although the red light has a longer wavelength than the blue one, in turn it has a lower energy than the blue light.

8 0
4 years ago
Determine the moment of inertia Ixx of the mallet about the x-axis. The density of the wooden handle is 860 kg/m3 and that of th
Yuki888 [10]

Complete Question

Diagram for this  shown on the first uploaded image

Answer:

The moment of inertia Ixx of the mallet about the x-axis is I{xx}= 0.119 kg \cdot m^2

Explanation:

From the question we are told that

        The density `of wooden handle is  \rho_w = 860 kg/m^3

        The density `of soft-metal head  is \rho_s =8000kg/m^3

Generally the mass of the wooden can be mathematically obtained with this formula

          m_w = \rho_w A_w l_w

Where A_w is mass of wooden handle which is  mathematically obtain with the formula

             A_w = \frac{\pi}{4} d^2_w

Where d_w is the diameter  of the wooden handle which from the diagram is

       27mm = \frac{27}{1000} = 0.027m

So  A_w = \frac{\pi}{4} * 0.027^2

      l_w is the length of the the wooden handle which is given in the diagram as   l_w = 315mm = \frac{315}{1000} = 0.315m

Substituting these value into the formula for mass

      m_w = 860 * (\frac{\pi}{4} * 0.027^2 ) *0.315

            = 0.155kg

Generally the mass of the soft-metal head can be mathematically obtained with this formula

           m_s = \rho_s A_s l_s

Where A_s is mass of soft-metal head which is  mathematically obtain with the formula

            A_s = \frac{\pi}{4} d^2_s

Where d_s is the diameter  of the soft-metal head which from the diagram is            

       36mm = \frac{36}{1000} = 0.036m

So  A_s = \frac{\pi}{4} * 0.036^2

 l_s is the length of the the soft-metal head which is given in the diagram

     as   l_s = 90mm = \frac{90}{1000} = 0.090m

Substituting these value into the formula for mass  

                  m_s = 8000 * (\frac{\pi}{4} * 0.036^2 ) *0.090

                       =0.733kg

Generally the mass moment of inertia about x-axis for the wooden handle is

                  (I_{xx})_w  =    [\frac{1}{3}m_w + l_w^2 ]  

Substituting values

                   (I_{xx})_w  =    [\frac{1}{3}*0.155 + 0.315^2 ]

                              =5.12*10^{-3}kg \cdot m^2  

Generally the mass moment of inertia about x-axis for the soft-metal head is

    (I_{xx})_s = [\frac{1}{12}m_s l_s ^2 + b^2]

Where b is the distance from the centroid to the axis of the head which is mathematically given as

                   b=l_w +\frac{d_s}{2}

Substituting values

                 b = 0.315 + \frac{0.036}{2}

                    = 0.336m

Now substituting values into the formula for mass moment of inertia about x-axis for soft-metal head

                            (I_{xx})_s = [\frac{1}{12} *0.733*  0.090^2 + 0.336^2]

                                      =0.113 kg \cdot m^2

Generally the mass moment of inertia about x-axis is mathematically represented as

         I_{xx} = (I_{xx})_w + (I_{xx})_s

                = [\frac{1}{3}m_w + l_w^2 ] + [\frac{1}{12}m_s l_s ^2 + b^2]

Substituting values

        I_{xx} = 5.12*10^{-3} +0.113

               I{xx}= 0.119 kg \cdot m^2

             

             

8 0
3 years ago
What is the speed, in m/s, of a wave on a cord if it has a wavelength of 4m and a period of 0.5 s
Fittoniya [83]
Using v=Π/p = 4/0.5 = 8ms-¹
8 0
3 years ago
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