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erica [24]
3 years ago
10

The lifting force, F, exerted on an airplane wing varies jointly as the area, A, of the wing's surface and the square of the pla

ne's velocity, v. The lift of a wing with an area of 190190 square feet is 95009500 pounds when the plane is going 220220 miles per hour. Find the lifting force on the wing if the plane slows down to 190190 miles per hour. (Leave the variation constant in fraction form or round to at least 5 decimal places.
Physics
1 answer:
Mrrafil [7]3 years ago
3 0

Answer:

F'=708.53 N

Explanation:

We have,

The lifting force, F, exerted on an airplane wing varies jointly as the area, A, of the wing's surface and the square of the plane's velocity, v. It means tat,

F=kAv^2

k is constant

If, A = 190 Ft², v = 220 mph, F = 950 pounds

Let's find k first from above data. So,

k=\dfrac{F}{Av^2}\\\\k=\dfrac{950}{190\times 220^2}\\\\k=0.0001033

It is required to find the lifting force on the wing if the plane slows down to 190 miles per hour. Let F' is the new force. So,

F'=0.0001033\times 190\times (190)^2\\\\F'=708.53\ \text{pounds}

So, the lifting force is 708.53 pounds if the plane slows down to 190 miles per hour.

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Then, replacing the values on the equation and solving for v_f, we get:

W_T+W_F=K_f-K_i\\88.6810-59.5840=5v_f^{2}\\29.097=5v_f^{2}

\frac{29.097}{5}=v_f^{2}\\\sqrt{5.8194}=v_f\\2.4123=v_f

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