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Umnica [9.8K]
3 years ago
15

By default, your numerical entry is scored as correct if it is within 1% of the correct answer. A rule of thumb is always to ent

er at least 3 digits for numerical questions. If the correct answer is 7.80009, which of the following entries would be counted as correct? That is, which entries are within WebAssign's default tolerance? (Select all that apply.)
7.80   7.6363   7.6  7.96   7.730   7.8703
Chemistry
1 answer:
IrinaK [193]3 years ago
6 0
1) Multiply the correct answer by 1% => 7.80009 * 1/100 = 0.0780009

2) Calculate minimum and maximum values:

a) Maximum: 7.80009 + 0.0780009 = 7.8780909

b) Minimum: 7.80009 - 0.0780009 = 7.7220891

3) Valid range: [7.7220891, 7.8780909]

4) Conclusion: 7.80, 7.730 and 7.80703 are inside the range and are inside the tolerance, while 7.6363, 7.6 and 7.76 are not.
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The following chart provides information on how fast leopards can accelerate
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If you start with 10ml of 0.75 m cu(no3)2 how much cu (s) in grams should be recovered in step #7
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3 years ago
If 2.60 g of NaBr are dissolved in enough water to make 160. mL of solution, what is the molar concentration of
navik [9.2K]

This problem has two parts; the first one asking for the concentration of NaBr given both its mass and volume and the second one asking for its volume given both mass and concentration. The answers turn out to be 0.158 M and 211 mL.

<h3>Molarity</h3>

In chemistry, the use of units of concentration depends on both the substances to analyze and their amounts. In such a way, for molarity, one needs the following relationship between the moles of solute and volume of solution:

M=\frac{n}{V}

Thus, for the first part of the problem we first calculate the moles in 2.60 g of NaBr via its molar mass:

2.60g*\frac{1mol}{102.89g} =0.0253mol

Next, we convert the 160. mL to L by dividing by 1000 in order to obtain 0.160 L to subsequently calculate the molarity:

M=\frac{0.0253mol}{0.160L}=0.158M

Next, since the moles remain the same and for the second part we are asked for the volume given the concentration, one can solve for the volume so as to obtain:

V=\frac{n}{M} =\frac{0.158M}{0.120mol/L}\\ \\V=0.211L

That in milliliters turns out to be:

V=0.211L*\frac{1000mL}{1L}=211mL

Learn more about molarity: brainly.com/question/10053901

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1 year ago
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