Use the ideal gas law PV = nRT and manipulate it to solve for n. PV/RT = n.
Convert to SI units:
660ml -> 0.660 L
27 degrees -> 300 K
Leave Pressure as is
Use 62.36368 for R becuase you are using mmHg for Pressure.
Now plug into the equation to get about 0.025928 mols. Divide the 3.30 grams by the mols to get about 127 g/mol.
Answer:
Option C. Pressure is directly proportional to the absolute temperature.
Explanation:
The ideal gas equation is given as:
PV = nRT
P = nRT/ V
Since n and V are constant, it means that P will be directly proportional to the absolute temperature
First find the molar masses of all of the compounds:
SrCl2 = 158.53g/mol
SrI2 = 341.43g/mol
SrO = 103.62g/mol
SrS = 119.68g/mo
Then find the molar mass of Sr in each of the compounds. Since there is only one Sr in every compound, the mass will be the same: 87.62g/mol Sr
Now divide the molar mass of Sr by each of compounds' masses:
SrCl2 = (87.62)/(158.53) = 0.553
SrI2 = (87.62)/(341.43) = 0.257
SrO = (87.62)/(103.62) = 0.846
SrS = (87.62)/(119.68) = 0.732
Now multiply each of the results by 100 to get the percent composition of Sr by mass:
(0.553)(100) = 55.3% Sr in SrCl2
(0.257)(100) = 25.7% Sr in SrI2
(0.846)(100) = 84.6% Sr in SrO
(0.732)(100) = 73.2% Sr in SrS
Thus SrO has the highest percent composition by mass of Sr
When the molecule undergoes chlorination with Cl2 on heating, the hydrogen atom of the alkyl group is replaced by the chlorine atom and form chloroalkanes. The molecule X containes three types of alkyl halides, therefore three different types of chloroalkanes are formed by the replacement of hydrogem atom linked to these alkyl groups. Thus the three different types of chloroalkanes are formed - primary, secondary, and thertiary chloroalkane. Chlorination is not selective so a mixture pf products results. The products formed by the reaction of the molecule with Y with Cl2 are shown on the attached file.
Answer:
7.17 g/mL
Explanation:
Density = Mass / Volume
Given mass of object : 80.4g
We are not given the objects volume, however we are given that when put inside of a container with 20.0mL water, the level of the water rises to 31.2 mL.
31.2 - 20 = 11.2
The water level rose 11.2 mL when the object was placed inside of the cylinder containing the water therefore the object has a volume of 11.2mL
Now to find it's density
recall that density = mass / volume
mass = 80.4 and volume = 11.2mL
so density = 80.4/11.2 = 7.17 g/mL
