Answer is: ion product for strontium chromate is 3·10⁻⁵.<span>
Balanced chemical reaction (dissociation) of
strontium chromate:
</span>Sr²⁺(aq) + CrO₄²⁻(aq) → SrCrO₄.<span>
Qsp(</span>SrCrO₄) = c(Sr²⁺)·(CrO₄²⁻).<span>
c(</span>Sr²⁺) = 2.00·10⁻² M.
c(CrO₄²⁻) = 1.50·10⁻³ M.
Q = 2.00·10⁻² M · 1.50·10⁻³ M.
Q = 0.00003 = 3·10⁻⁵ M².
A cation is a positive ion. That means it lost an electron.
