A) Using paper chromatography to separate pigments by density
The correct answer for the question that is being presented above is this one: "<span>16.728 g."</span>
Given that
ΔHsolid = -5.66 kJ/mol.
This means that 5.66 kJ of heat is released when 1 mole of NH3 solidifies
When 5.57 kJ of heat is released
amount of NH3 solidifies = 5.57/5.66 = 0.984 moles
<span>molar mass of NH3 = 17 g/mole </span>
<span>1 mole of NH3 = 17 g </span>
So, 0.984 moles of NH3 = 17 X 0.984 = 16.728 g
Carbonyl Compounds containing
alpha proton readily donates alpha acidic proton when treated with
strong Base. In given statement <span>
2-phenylacetaldehyde is converted into Enolate and Enolates acts as a nucleophile and attacks carbonyl group of
Benzaldehyde. The mechanism of given reaction is as follow, the movement of electrons is shown by
RED arrows,</span>
Answer: V2= 0.224L
Explanation:
P1=3.55atm, V2= 7.35L, T1= 290, P2= 123atm, V2=?, T2= 307K
Applying general gas equation
P1V1/T1= P2V2/T2
Substitute and Simplify
3.55×7.35/290 = 123×V2/307
V2= 0.224L
