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3 years ago

10

How many energy levels? Explain your answer.

2 answers:

Ivanshal [37]3 years ago

8 0

The maximum numbers of electrons possible for the first four energy levels are shown in the Figure above. For example, energy level I can hold a maximum of two electrons, and energy level II can hold a maximum of eight electrons. The maximum number depends on the number of orbitals at a given energy level.

Anarel [89]3 years ago

5 0

Answer:

The maximum numbers of electrons possible for the first four energy levels are shown in the Figure above. For example, energy level I can hold a maximum of two electrons, and energy level II can hold a maximum of eight electrons. The maximum number depends on the number of orbitals at a given energy level.

Explanation:

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Given the heat change per mole for the combustion of methanol (-726 kJ/mol), predict the heat change that would occur if 0.200 m

DochEvi [55]

Answer:

-145.2kJ

Explanation:

Enthalpy is an extensive property as its value depends on the amount of substance present in the system.

If the enthalpy for one mole of methanol = -726 kJ/mol;

The Enthalpy for 0.2 mol is given as;

Enthalpy = 0.200 * 726

Enthalpy = -145.2kJ

It would take -145.2kJ for 0.200 mol of methanol to undego the combustion reaction.

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2 years ago

Which equation is an example of a synthesis reaction

storchak [24]

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2 years ago

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Which atoms in the pair has the larger atomic radius ? Help please !!

Ne4ueva [31]

A

1. Potassium, K.

2. Calcium, Ca.

3. Gallium, Ga.

4. Carbon, C.

5. Bromine, Br.

6. Barium, Ba.

7. Silicon, Si.

Explanation:

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2 years ago

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pplication)Using multiple models simultaneously: This FNT refers to a processinvolving three moles of a diatomic gas (which beha

Fiesta28 [93]

Complete Question

Questions Diagram is attached below

Answer:

* $W=1142.86Joule$

* $Q=997.7J$

* $H=2140.5J$

Explanation:

From the question we are told that:

Temperature $T=337K$

Pressure $P=(60-55)Pa*10^5$

Volume $V=(1.6-1.4)m^3*10^{-3}$

Generally the equation for gas Constant is mathematically given by

$\frac{P_2}{P_1}=\frac{V_1}{V_2}^n$

$\frac{55*10^5}{60*10^5}=\frac{1.4*10^{-3}}{1.6*10^{-3}}^n$

$n=0.65$

Therefore

Work-done

$W=\int{pdv}$

$W=\frac{55*10^5*1.6*10^{-3}*60*10^5*1.4*10^{-3}}{1-0.65}$

$W=1142.86Joule$

Generally the equation for internal energy is mathematically given by

$Q=mC_vdT\\\\Q=\frac{3*1*3.314*16}{1.4-1}$

$Q=997.7J$

Therefore

$H=Q+W$

$H=997.7J-11.42.9$

$H=2140.5J$

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2 years ago

If you wanted to know how big a tiger is which measurements would you use?

Elan Coil [88]

I think the answer is
D. Meter Second
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3 years ago

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