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wariber [46]
3 years ago
15

Unlike a physical change, a chemical change is not easily what?

Physics
1 answer:
krok68 [10]3 years ago
8 0

because a chemical change takes time

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Ezra is pulling a sled, filled with snow, by pulling on a rope attached to the sled. The rope makes an angle θ with respect to t
svetoff [14.1K]

Answer:

Explanation:

Given

rope makes an angle of \theta

Mass of sled and snow is m

Normal Force =F_N

applied Force is F

as Force is pulling in nature therefore normal reaction is given by

F_N=mg-F\sin \theta

Also F\cos \theta =f_r

f_r=\mu _k\cdot F_N

f_r=\mu _k\cdot (mg-F\sin \theta )

F\cos \theta =\mu _kF_N-------1

F\sin \theta =mg-F_N---------2

Squaring 1 & 2 and then adding

F^2=(\mu _kF_N)^2+(mg-F_N)^2

F=\sqrt{(\mu _kF_N)^2+(mg-F_N)^2}

Substitute value of F in 1

cos\theta =\frac{\mu _KF_N}{\sqrt{(\mu _kF_N)^2+(mg-F_N)^2}}

\theta =cos^{-1}(\frac{\mu _KF_N}{\sqrt{(\mu _kF_N)^2+(mg-F_N)^2}})

8 0
3 years ago
A 0.144 kg baseball is moving towards home plate with a speed of 43.0 m/s when it is bunted. the bat exerts an average force of
Ganezh [65]

As per impulse momentum theorem we know that

F\Delta t = m(v_f - v_i)

now here we will have

F = 6.50 \times 10^3 N

t = 1.30 ms

m = 0.144 kg

v_i = -43 m/s

now we need to find final speed using above formula

(6.50 \times 10^3)(1.30 \times 10^{-3}) = 0.144 ( v_f - (-43))

v_f = 15.7 m/s

so final speed is given as above

6 0
3 years ago
Based on their locations on the periodic table, which two elements would you
Nat2105 [25]

Answer:

i think it would be B. Aluminum, Al and D. Boron, B

Explanation:

since they're both in group 13 and they forms a 3+ ion

6 0
3 years ago
Read 2 more answers
12000 inches to yards
Nutka1998 [239]

ANSWER

\begin{equation*} 333.33\text{ yds} \end{equation*}

EXPLANATION

We want to convert 12000 inches to yards.

To do this, divide the value in inches by 36:

\begin{gathered} 1\text{ in }=\frac{1}{36}\text{ yd} \\  \\ 12000\text{ in }=\frac{12000}{36}\text{ yds }=333.33\text{ yds} \end{gathered}

That is the answer.

4 0
1 year ago
Suppose 3 mol of neon (an ideal monatomic gas) at STP are compressed slowly and isothermally to 0.19 the original volume. The ga
Radda [10]

Answer:

a. 273 K b. 90.1 K c. 5.26 atm d. 0.33 atm

Explanation:

For isothermal expansion PV = constant

So, P₁V₁ = P₂V₂ where P₁ = initial pressure of gas = 1 atm (standard pressure), V₁ = initial volume of gas, P₂ = final pressure of gas and V₂ = final volume of gas,

So, P₁V₁ = P₂V₂

P₂ = P₁V₁/V₂

Since V₂/V₁ = 0.19,

P₂ = P₁V₁/V₂

P₂ = 1 atm (1/0.19)  

P₂ = 5.26 atm

For an adiabatic expansion, PVⁿ = constant where n = ratio of molar heat capacities = 5/3 for monoatomic gas

So, P₂V₂ⁿ = P₃V₃ⁿ where P₂ = initial pressure of gas = 5.26 atm, V₂ = initial volume of gas, P₃ = final pressure of gas and V₃ = final volume of gas,

So, P₂V₂ⁿ = P₃V₃ⁿ

P₃ = P₂V₂ⁿ/V₃ⁿ

P₃ = P₂(V₂/V₃)ⁿ

Since V₃ = V₁ ,V₂/V₃ = V₂/V₁ = 0.19

1/0.19,

P₃ = P₂(V₂/V₃)ⁿ

P₃ = 5.26 atm (0.19)⁽⁵/³⁾

P₃ = 5.26 atm × 0.0628

P₃ = 0.33 atm

Using the ideal gas equation

P₃V₃/T₃ = P₄V₄/T₄ where P₃ = pressure after adiabatic expansion = 0.33 atm , V₃ = volume after adiabatic expansion, T₃ = temperature after adiabatic expansion  P₄ = initial pressure of gas = P₁ = 1 atm , V₄ = initial volume of gas = V₁ and T₄ = initial temperature of gas = T₁ = 273 K (standard temperature)

P₃V₃/T₃ = P₄V₄/T₄

T₃ = P₃V₃T₄/P₄V₄    

T₃ = (P₃/P₄)(V₃/V₄)T₂

Since V₃ = V₄ = V₁ and P₄ = P₁

V₃/V₄ = 1 and P₃/P₄ = P₃/P₁

T₃ = (P₃/P₁)(V₃/V₄)T₂

T₃ = (0.33 atm/1 atm)(1)273 K  

T₃ = 90.1 K

So,

a. The highest temperature attained by the gas is T₁ = 273 K

b. The lowest temperature attained by the gas = T₃ = 90.1 K

c. The highest pressure attained by the gas is P₂ = 5.26 atm

d. The lowest pressure attained by the gas is P₃ = 0.33 atm

6 0
3 years ago
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