Question

The load across a 12 v battery consists of a series combination of three resistors 45 ω, 55 ω, and 35 ω. what is the total resistance of the load? answer in units of ω.

Answer 1

For n resistors in series, the equivalent resistance is given by the sum of the resistances:
$R_{eq} = R_1 + R_2 + ... + R_n$

In this problem, we have three resistors, so the equivalent resistance of the load is the sum of the resistances of the three resistors:
$R_{eq}=45 \Omega + 55 \Omega + 35 \Omega =135 \Omega$