Ask question

Ask question

All categories

AleksandrR [38]

4 years ago

11

The load across a 12 v battery consists of a series combination of three resistors 45 ω, 55 ω, and 35 ω. what is the total resis

tance of the load? answer in units of ω.

1 answer:

zubka84 [21]4 years ago

5 0

For n resistors in series, the equivalent resistance is given by the sum of the resistances:
$R_{eq} = R_1 + R_2 + ... + R_n$

In this problem, we have three resistors, so the equivalent resistance of the load is the sum of the resistances of the three resistors:
$R_{eq}=45 \Omega + 55 \Omega + 35 \Omega =135 \Omega$

You might be interested in

In some proton accelerators, proton beams are directed toward each other for head-on collisions. Suppose that in such an acceler

ipn [44]

Answer:

a) 0.9995c

b) 5641MeV

c) 91670 MeV

Explanation:

(a) The speed of approach is given by the formula:

$u=\frac{v_1+v_2}{1+\frac{v_1v_2}{c}}=\frac{2(0.9898c)}{1+\frac{(0.9898)^2c^2}{c^2}}=0.99995c$

(b) the kinetic energy is given by:

$E_k=m_0c^2[\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}-1]$

by replacing c=3*10^8m/s, m_0=1.67*10^{-27}kg we obtain:

$E_k=5641MeV$

(c) in the rest frame of the other proton we have:

$E_k=m_0c^2[\frac{1}{\sqrt{1-\frac{u^2}{c^2}}}-1]$

by replacing we get

$E_k=91670MeV$

hope this helps!!

7 0

3 years ago

An object of mass m attached to a spring of force constant k oscillates with simple harmonic motion. The maximum displacement fr

Lady_Fox [76]

An object of mass m attached to a spring of force constant k oscillates with simple harmonic motion. The system's potential energy when kinetic energy of (3/4) E is (1/8) k A².

<h3>What is mechanical energy?</h3>

Mechanical energy is the sum of potential energy and kinetic energy.

Total mechanical energy = P.E max = K.E max

Total mechanical energy = K.E +P.E

Given is the kinetic energy is (3/4)E.

E= (3/4)E + P.E

P.E = (1/4) E

Maximum potential energy =E = (1/2) k A²

Here. A is the maximum displacement and k is the spring constant.

The potential energy at kinetic energy of (3/4) E is

P.E = (1/4)E = (1/8) k A²

Therefore, the system's potential energy when kinetic energy of (3/4) E is (1/8) k A².

Learn more about mechanical energy.

brainly.com/question/20904200

#SPJ4

6 0

2 years ago

A 67 Vrms source is placed across a load that consists of a 12 ohm resistor in series with an capacitor whose reactance is 5 ohm

SVETLANKA909090 [29]

a) The average true power is 318.3 W

b) The reactive power is 132.6 W

c) The apparent power is 344.8 W

d) The power factor is 0.92

Explanation:

a)

For a circuit made of a resistor and a capacitor, the average (true) power is given by the resistive part of the circuit only.

Therefore, the average true power is given by:

$P=I^2R$

where

I is the current

R is the resistance

In this problem, we have

V = 67 V (rms voltage)

$R=12 \Omega$ is the resistance of the load

$X=5\Omega$ is the reactance of the circuit

First we have to find the impedance of the circuit:

$Z=\sqrt{R^2+X^2}=\sqrt{12^2+5^2}=13 \Omega$

Then we can find the current in the circuit by using Ohm's law:

$I=\frac{V}{Z}=\frac{67}{13}=5.15 A$

Therefore, the average true power is

$P=I^2R=(5.15)^2(12)=318.3 W$

b)

The reactive power of a circuit consisting of a resistor and a capacitor is the power given by the capacitive part of the circuit.

Therefore, it is given by

$Q=I^2X$

where

I is the current

X is the reactance of the circuit

In this circuit, we have

$I=5.15 A$ (current)

$X=5 \Omega$ (reactance)

Therefore, the reactive power is

$Q=(5.15)^2(5)=132.6W$

c)

In a circuit with a resistor and a capacitor, the apparent power is given by both the resistive and capacitive part of the circuit.

Therefore, it is given by

$S=I^2Z$

where

I is the current

Z is the impedance of the circuit

Here we have

I = 5.15 A (current)

$Z=13 \Omega$ (impedance)

Therefore, the apparent power is

$S=I^2 Z=(5.15)^2(13)=344.8 W$

d)

For a circuit with a resistor and a capacitor, the power factor is the ratio between the true power and the apparent power. Mathematically:

$PF=\frac{P}{S}$

where

P is the true power

S is the apparent power

For this circuit, we have

P = 318.3 W (true power)

S = 344.8 W (apparent power)

So, the power factor is

$PF=\frac{318.3}{344.8}=0.92$

Learn more about power and circuits:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

#LearnwithBrainly

3 0

3 years ago

What is the upward force that makes things float?

rewona [7]

I think its Buoyancy

8 0

3 years ago

Read 2 more answers

Why does Chelsea see sparks as she removes her clothes from the clothes dryer?

Ne4ueva [31]

Static electricity!

8 0

4 years ago

Read 2 more answers