Sure ! Here's one way to look at it that nobody ever tells you:
Remember:
-- A fraction with the same thing on the top and bottom is equal to ' 1 '.
-- You can multiply a quantity by ' 1 ' all day long without changing its value.
In order to convert units, you multiply the original quantity by one or more fractions. Each fraction has the same thing on top and bottom, but in different units, so it's equal to ' 1 '. Then you go through the expression that you've built, and 'cancel' things ... dividing a unit out where it appears on both the top and bottom.
Example:
How many seconds are there in 1 day ?
(Convert one day to units of seconds.)
(1 day) x (24 hr/day) x (60min/hr) x (60 sec/min)
That's 1 day, multiplied by 3 fractions. Each fraction is equal to ' 1 ' because it has the same thing on top and bottom, only in different units.
Now, look at the first 2 terms. They have 'day' on top and 'day' on the bottom, so 'day' can be 'canceled' (actually divided) out of the top and bottom.
Similarly, the 2nd and 3rd terms have 'hour' on top and bottom, so 'hour' can be canceled and disappear from the whole expression. The 3rd and 4th terms have 'minute' on the top and bottom, so 'minute' can be canceled.
Finally, the only unit that's still there and hasn't been cancelled is 'second'. The whole expression now says
(1) x (24) x (60) x (60 seconds) = 86,400 seconds
and <em>there's</em> the conversion of units from 'day' to 'second'.
The whole trick is to pick the right fractions, and to decide whether to write each fraction either right-side-up or upside-down. The idea is to decide which unit you want to get rid of, and then arrange things so that it's on top once and on the bottom once, so that you can cancel it and make it disappear.
And that's what I can give you on the topic of converting units. To me, it's always been very helpful.
Answer:
Baka makita mo si behati dun
Answer:
<em>0.45 N</em>
Explanation:
<em>Let Recall that,</em>
<em> The power formula is: </em>
<em> P = E²/R </em>
Let A = the magnetic field
<em>Let L = length of wire = 9.00cm = 0.09 m </em>
let R = resistance of wire = 0.320 Ω
let v = velocity of the wire = 4 m/s
<em>Let E = across the wire voltage </em>
Let P = the power of the wire = 4.3 W
To Solve for E:
<em>The formula of E = √PR </em>
The Voltage from a magnetic field is given as,
E = vAL
We therefore Use E = E
√PR = vAL
to solve for A,
A= √PR/vL
BA= √4.3(0.32)/(4)(.09) -=0.173
A = 0.173 wA/m²
Let F be the pulling force
Let I be the current in the wire
P = I²R
<em>I = √P/R </em>
F = IAL
F = √P/RAL
F = √4.3/.32(0.173)(.09)
<em>F = 0.45N</em>
Answer:
a) 1321.45 N
b) 1321.45 N
c) 2.66 m/s^2
d) 2.21*10^-22 m/s^2
Explanation:
Hello!
First of all, we need to remember the gravitational law:
Were
G = 6.67428*10^-11 N(m/kg)^2
m1 and m2 are the masses of the objects
r is the distance between the objects.
In the present case
m1 = earth's mass = 5.9742*10^24 kg
m2 = 497 kg
r = 1.92 earth radii = 1.92 * (6378140 m) = 1.2246*10^7 m
Replacing all these values on the gravitational law, we get:
F = 1321.45 N
a) and b)
Both bodies will feel a force with the same magnitude 1321.45 N but directed in opposite directions.
The acceleration can be calculated dividing the force by the mass of the object
c)
a_satellite = F/m_satellite = ( 1321.45 N)/(497 kg)
a_satellite = 2.66 m/s^2
d)
a_earth = F/earth's mass = (1321.45 N)/( 5.9742*10^24 kg)
a_earth = 2.21*10^-22 m/s^2
Explanation:
electric current is the answer