A remote controlled car starts from rest and accelerates at 2 m/s² for 6.5 seconds. What is the final velocity of the car after
1 answer:
Answer:
The final velocity of the car after the acceleration takes place is 13 m/s.
Explanation:
The final velocity can be calculated using the following equation:
Where:
: is the initial velocity = 0 (starts from rest)
a: is the acceleration = 2 m/s²
t: is the time = 6.5 s
Hence, the final velocity is:
Therefore, the final velocity of the car after the acceleration takes place is 13 m/s.
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Answer:
v(t) = 27 units
Explanation:
The function s(t) represents the position of an object at time t moving along a line such that,
and
We need to find the average velocity of the object over the interval of time [2,6]. The velocity of the object is equal to the total distance divided by time. It is given by :
v(t) = 27 units
So, the average velocity of the object is 27 units. Hence, this is the required solution.
Answer:
28.8 meters
Explanation:
We must first determine at which velocity the ball hits the water. To do so we will:
1) Assume no air resistance.
2) Use the Law of conservation of mechanical energy: E=K+P
Where
E is the mechanical energy (which is constant)
K is the kinetic energy.
P is the potential energy.
With this we have
Where:
m is the balls's mass <- we will see that it cancels out and as such we don't need to know it.
v is the speed when it hits the water.
g is the gravitational constant (we will assume g=9.8.
h is the height from which the ball fell.
Because when we initially drop the ball, all its energy is potential (and ) and when it hits the water, all its energy is kinetic (
. And all that potential was converted to kinetic energy.
Now, from we can deduce that
Therefore v=9.6
Now, to answer how deep is the lake we just need to multiply that speed by the time it took the ball to reach the bottom.
So D=9.6*3
=28.8
Which is our answer.