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vesna_86 [32]
4 years ago
11

A remote controlled car starts from rest and accelerates at 2 m/s² for 6.5 seconds. What is the final velocity of the car after

the acceleration takes place?
Physics
1 answer:
AleksandrR [38]4 years ago
4 0

Answer:

The final velocity of the car after the acceleration takes place is 13 m/s.

Explanation:

The final velocity can be calculated using the following equation:

V_{f} = V_{0} + at

Where:

V_{0}: is the initial velocity = 0 (starts from rest)

a: is the acceleration = 2 m/s²

t: is the time = 6.5 s

Hence, the final velocity is:

V_{f} = V_{0} + at = 0 + 2 m/s^{2}*6.5 s = 13 m/s

Therefore, the final velocity of the car after the acceleration takes place is 13 m/s.

I hope it helps you!

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Margarita [4]
Thank you for posting your question here at brainly. Feel free to ask more questions.  
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3 years ago
The motion of a particle is described by the position function s(t) = 2t - 15t +33t+17,t&gt;0 , where is measured in seconds and
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The time when the particle is at rest is at 1.63 s or 3.36 s.

The velocity is positive at when the time of motion is at 0.

The total distance traveled in the first 10 seconds is 847 m.

<h3>When is a particle at rest?</h3>
  • A particle is at rest when the initial velocity of the particle is zero.

The time when the particle is at rest is calculated as follows;

s(t) = 2t³ - 15t² + 33t + 17

v = \frac{ds}{dt} = 6t^2 -30t + 33\\\\at \ rest, \ v = 0\\\\6t^2 - 30t + 33 = 0\\\\6(t- \frac{5}{2} )^2- \frac{9}{2} = 0\\\\t = 1.63\ s \ \ or \ 3.36 \ s

The velocity is positive at when the time of motion is as follows;

0.

The total distance traveled in the first 10 seconds is calculated as follows;

2(10)^3 - 15(10)^2 + 33(10) + 17 = 847 \ m

Learn more about motion of particles here: brainly.com/question/11066673

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2 years ago
Ron is on a Ferris wheel of radius 30 ft that turns counterclockwise at a rate of one revolution every 12 seconds. The lowest po
alexgriva [62]

Answer:

x = 30cos\frac{\pi}{6}t

y = 30sin\frac{\pi}{6}t + 45

Explanation:

1 full revolution is 2\pi. let \theta be the angle of Ron's position.

At t = 0. \theta = 0

one full revolution occurs in 12 sec, so his angle at t time is

\theta =2\pi \frac{t}{12} = \frac{\pi}{6}t

r is radius of circle and it is given as

x = rcos\theta

y = rsin\theta

for r = 30 sec

x = 30cos\frac{\pi}{6}t

y = 30sin\frac{\pi}{6}t

however, that is centered at (0,0) and the positioned at time t = 0 is (30,0). it is need to shift so that the start position is (30,45). it can be done by adding to y

x = 30cos\frac{\pi}{6}t

y = 30sin\frac{\pi}{6}t + 45

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