Answer:
Loss, 
Explanation:
Given that,
Mass of particle 1, 
Mass of particle 2, 
Speed of particle 1, 
Speed of particle 2, 
To find,
The magnitude of the loss in kinetic energy after the collision.
Solve,
Two particles stick together in case of inelastic collision. Due to this, some of the kinetic energy gets lost.
Applying the conservation of momentum to find the speed of two particles after the collision.



V = 6.71 m/s
Initial kinetic energy before the collision,



Final kinetic energy after the collision,



Lost in kinetic energy,



Therefore, the magnitude of the loss in kinetic energy after the collision is 10.63 Joules.
I think it’s R=U/I = 120/5 = 24
Answer: Galileo's laws of Motion determined that the natural state of an object is rest or uniform motion, objects always have a velocity, sometimes that velocity has a magnitude of zero rest. objects resist change in motion, which is called inertia.
Explanation:
Answer:
5.08*10^{-13}N
Explanation:
With this information we can calculate the velocity of the proton by taking into account the kinetic energy of the proton:

The magnitude of the magnetic force will be:

hope this helps!