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3 years ago

How can a magnet attract or repel another magnet even if they are not touching?

Physics

1 answer:

lakkis [162]3 years ago

4 0

Answer:

Magnetic forces are non contact forces; they pull or push on objects without touching them. Magnets are only attracted to a few 'magnetic' metals and not all matter. Magnets are attracted to and repel other magnets.

Explanation:

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Calculate the number of molecules/m3 in an ideal gas at stp.

vivado [14]

STP (Standard Temperature and Pressure) has the following conditions:

Temperature = 273.15 K = 0°C
Pressure = 101325 Pa = 101.325 KPa = 1 atm

We also know that 1 mole = 6.022x10^23 molecules

Using the ideal gas equation: PV=nRT

n/V = P/RT

molecules/V = P*6.022x10^23/RT
molecules/V = 101325 Pa (6.022x10^23 molecules/mole)/ (8.314 Pa-m3/mol-K)(273.15K)

molecules/V = 7.339x10^27 molecules/m^3 - Final answer

4 0

4 years ago

A distracted driver is driving towards a turn where the edge of the road leads into a 75.0 m cliff. The velocity of the vehicle

Vlada [557]

As long as the car is on the road, it moves with a constant speed of 80km/h.

As soon as the car starts to fall down the cliff, it follows a parabolic motion. It means that it still moves with constant speed along the x axis, but it also starts to move along the y axis, with constant acceleration (i.e. the acceleration due to gravity).

The good thing about parabolic motions is that the two motions along the x and y axes are completely separable.

So, first of all, we need to know how long it takes for an object to fall for 75m. The equation of a constantly accelerated motion is

$s=s_0+v_0t+\dfrac{1}{2}at^2$

Where $s_0$ is the initial position, $v_0$ is the initial speed, and $a$ is the constant rate of acceleration. In our case, we start from an initial height of 75m, an initial (vertical!) speed of zero, and our acceleration is $-g$ . So, our equation becomes

$s=75-\dfrac{g}{2}t^2$

And we want to solve for the time when $s=0$ (i.e. we want to know how long will it take for the object to reach the ground). We have

$0=75-\dfrac{g}{2}t^2 \iff 75=\dfrac{g}{2}t^2 \iff \dfrac{2\cdot75}{g}=t^2 \iff t=\sqrt{\dfrac{150}{g}}$

(I'm discarding the negative solution because it wouldn't make sense)

Now that we've used the vertical motion to find out the falling time, we can go back to the horizontal motion. We know that the car moves for a certain amount of time at a certain speed. So, we simply have to plug our values in the $s=vt$ equation, to get

$s=80\sqrt\dfrac{150}{g}}$

This is how far from the base of the cliff the vehicle lands.

3 0

3 years ago

Neo and Morpheus's masses have gained a velocity (not equal to zero) which means their momentum is now _____ .

Arte-miy333 [17]

<span>Neo and Morpheus's masses have gained a velocity (not equal to zero) which means their momentum is now based on gravity and friction alone.</span>

6 0

3 years ago

Read 2 more answers

I don’t know what to do

zavuch27 [327]

Answer:

So increasing the voltage increases the charge in direct proportion to the voltage. If the voltage exceeds the capacitors rated voltage, the capacitor may fail due to breakdown of the dielectric between the two plates that make up the capacitor.

Explanation:

A option.

7 0

3 years ago

How does an inclined plane work? A A small input force is exerted over a long distance. B A large output force is exerted over a

zavuch27 [327]

An inclined plane, just like all simple machines, makes work easier. I think it is a type of simple machines. Therefore, I think the best answer is A.

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3 years ago