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malfutka [58]
3 years ago
5

Which statements are true concerning Newton's law of gravitation? The gravitational force is related to the mass of each object.

The gravitational force on a satellite is less at an altitude of 500 km above the Earth than at an altitude of 1000 km. A large and a small object are gravitationally attracted to each other. The magnitude of the gravitational force on the larger object is greater than on the smaller. The gravitational force is an attractive force. The gravitational force between the Earth and a person is constant, no matter how high the person is above the surface of the Earth.
Physics
1 answer:
OLEGan [10]3 years ago
5 0

Answer:

The gravitational force is related to the mass of each object.

The gravitational force is an attractive force.

Explanation:

Gravitational force is a long range force of attraction between any two masses.

Mathematically given as :

F=G.\frac{m_1.m_2}{r^2}

where:

m_1 & m_2 are the masses

r= distance between the center of mass of the two objects.

G= gravitational constant = 6.67\times 10^{-11} m^3.kg^{-1}.s^{-2}

From the above relation of eq. (1) it is clear that,

Gravitational force is inversely proportional to the square of the distance and directly proportional to the masses.

The mass of an object is independent of its size due to the fact that density may vary for different objects.

The force of gravity varies with height as:

\frac{g}{g_x} =(\frac{r_x}{r} )^2

where:

g=9.8\,m.s^{-2}

g_x= gravity at height r_x of the center of mass of the object from the center of mass of the earth.

and we know that force:

F=m\times g

where: m= mass of the object.

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Two spherical objects have masses 447 kg and 285 kg. Their centers are separated by a distance of 27 m. Find the gravitational a
jonny [76]

Answer:

1.2 * 10' -8N (Check attachment

Explanation:

Check attachment

5 0
3 years ago
A 49.0 kg wheel, essentially a thin hoop with radius 0.730 m, is rotating at 114 rev/min. It must be brought to a stop in 22.0 s
belka [17]

Explanation:

Mass of the wheel, m = 49 kg

Radius of the hoop, r = 0.73 m

Initial angular speed of the wheel, \omega_i=114\ rev/min = 11.93\ rad/s

Final angular speed of the wheel, \omega_f=0

Time, t = 22 s

(a) If I is the moment of inertia of the hoop. It is equal to,

I=mr^2

I=49\times (0.73)^2

I=26.11\ kg-m^2

We know that the work done is equal to change in kinetic energy.

W=\Delta E

W=\dfrac{1}{2}I(\omega_f^2-\omega_i^2)

W=-\dfrac{1}{2}\times 26.11\times (11.93^2)

W = -1858.05 Joules

(b) Let P is the average power. It is given by :

P=\dfrac{W}{t}

P=\dfrac{1858.05\ J}{22\ s}

P =84.45 watts

Hence, this is the required solution.

4 0
3 years ago
Can anyone please help me with answering this question? : An accelerating (speeding up) body has a Net Force acting in the direc
Katarina [22]
That's true.

Netwon's second law states that the resultant of the forces F acting on a body is equal to the product between its mass m and its acceleration a:
\sum F = ma
This means that if the net force acting on an object is different from zero (term on the left), than the acceleration of the object (term on the right) must be different from zero as well, and therefore the body is accelerating.

In particular, both F and a in the equation are vectors: this means that if the acceleration is positive, F and a have the same direction. In this problem, the acceleration is positive (because the object is speeding up), therefore the force and the acceleration have same direction.
7 0
4 years ago
(3.) A tourist travels 320 km in 3.6 h. What is her average speed for the trip?
solmaris [256]

Answer:

The average speed of the tourist is 88.89 km/h

Explanation:

Given;

distance of travel, d = 320 km

time of travel, t = 3.6 h

Average speed is given as;

average speed = distance / time

average speed = 320 km / 3.6 h

average speed = 88.89 km/ h

Therefore, the average speed of the tourist is 88.89 km/h

5 0
3 years ago
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