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malfutka [58]
3 years ago
5

Which statements are true concerning Newton's law of gravitation? The gravitational force is related to the mass of each object.

The gravitational force on a satellite is less at an altitude of 500 km above the Earth than at an altitude of 1000 km. A large and a small object are gravitationally attracted to each other. The magnitude of the gravitational force on the larger object is greater than on the smaller. The gravitational force is an attractive force. The gravitational force between the Earth and a person is constant, no matter how high the person is above the surface of the Earth.
Physics
1 answer:
OLEGan [10]3 years ago
5 0

Answer:

The gravitational force is related to the mass of each object.

The gravitational force is an attractive force.

Explanation:

Gravitational force is a long range force of attraction between any two masses.

Mathematically given as :

F=G.\frac{m_1.m_2}{r^2}

where:

m_1 & m_2 are the masses

r= distance between the center of mass of the two objects.

G= gravitational constant = 6.67\times 10^{-11} m^3.kg^{-1}.s^{-2}

From the above relation of eq. (1) it is clear that,

Gravitational force is inversely proportional to the square of the distance and directly proportional to the masses.

The mass of an object is independent of its size due to the fact that density may vary for different objects.

The force of gravity varies with height as:

\frac{g}{g_x} =(\frac{r_x}{r} )^2

where:

g=9.8\,m.s^{-2}

g_x= gravity at height r_x of the center of mass of the object from the center of mass of the earth.

and we know that force:

F=m\times g

where: m= mass of the object.

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Answer:

209 mph

Explanation:

V = Speed of bird in still air

v = Speed of wind = 44 mph

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D_{1} = distance traveled with the wind = 9292 mi

t_{1} = time taken to travel the distance with wind

Time taken to travel the distance with wind is given as

t_{1} = \frac{D_{1}}{V + v}

t_{1} = \frac{9292}{V + 44}                              eq-1

Consider the motion of the bird with the wind

D_{2} = distance traveled against the wind = 6060 mi

t_{2} = time taken to travel the distance against wind

Time taken to travel the distance against wind is given as

t_{2} = \frac{D_{2}}{V + v}

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As per the question,

Time taken with the wind = Time taken against the wind

t_{1} = t_{2}

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3232V = 675488

V = 209 mph

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3 years ago
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