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malfutka [58]
3 years ago
5

Which statements are true concerning Newton's law of gravitation? The gravitational force is related to the mass of each object.

The gravitational force on a satellite is less at an altitude of 500 km above the Earth than at an altitude of 1000 km. A large and a small object are gravitationally attracted to each other. The magnitude of the gravitational force on the larger object is greater than on the smaller. The gravitational force is an attractive force. The gravitational force between the Earth and a person is constant, no matter how high the person is above the surface of the Earth.
Physics
1 answer:
OLEGan [10]3 years ago
5 0

Answer:

The gravitational force is related to the mass of each object.

The gravitational force is an attractive force.

Explanation:

Gravitational force is a long range force of attraction between any two masses.

Mathematically given as :

F=G.\frac{m_1.m_2}{r^2}

where:

m_1 & m_2 are the masses

r= distance between the center of mass of the two objects.

G= gravitational constant = 6.67\times 10^{-11} m^3.kg^{-1}.s^{-2}

From the above relation of eq. (1) it is clear that,

Gravitational force is inversely proportional to the square of the distance and directly proportional to the masses.

The mass of an object is independent of its size due to the fact that density may vary for different objects.

The force of gravity varies with height as:

\frac{g}{g_x} =(\frac{r_x}{r} )^2

where:

g=9.8\,m.s^{-2}

g_x= gravity at height r_x of the center of mass of the object from the center of mass of the earth.

and we know that force:

F=m\times g

where: m= mass of the object.

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A golf ball is hit horizontally off the edge of a 30 m high cliff and lands a distance of 25 m from the edge of the cliff. What
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Answer:

V₀y = 0 m/s

t = 2.47 s

V₀ₓ = 61.86 m/s

Vₓ = 61.86 m/s

Explanation:

Since, the ball is hit horizontally, there is no vertical component of velocity at initial point. So, the initial vertical velocity (V₀y) will beL

<u>V₀y = 0 m/s</u>

For the initial vertical velocity of golf ball we consider the vertical motion and apply 2nd equation of motion:

Y = V₀y*t + (0.5)gt²

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t = time to hit the ground = ?

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t² = 30 m/4.9 m/s²

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<u>t = 2.47 s</u>

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V₀ₓ = Xt

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V₀ₓ = Initial vertical Velocity = ?

X = Horizontal Distance = 25 m

Therefore,

V₀ₓ = (25 m)(2.47 s)

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Due, to uniform motion in horizontal direction:

Final Vertical Velocity = Vₓ = V₀ₓ

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Answer:

-True  - True  - true   - false -false - false

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