Volatile organic compounds can be detected by hydrogeologists in the field or labs because of the odor of the vapors emitted from the groundwater and/or soil samples.
<h3>What are volatile substances?</h3>
Volatile substances are substances which can easily vaporize or change to gaseous state.
Volatile substances can either be solids or liquids but are mostly liquids.
Example of volatile substances include ether, petrol, chocolate.
The presence of volatile substances can be detected by the gases they release which may have characteristic odors.
Therefore, volatile organic compounds can be detected by hydrogeologists in the field or labs because of the odor of the vapors emitted from the groundwater and/or soil samples.
Learn more about volatile compounds at: brainly.com/question/25403770
Answer:
a. Oxygen gas is limiting
Explanation:
hydrogen gas and oxygen gas are reacted to form water
2H₂ + O₂ → 2H₂O
the above balanced equation shows that 2 moles of H₂ is required for 1 mole of O₂
Given equal masses of H₂ and O₂
assuming 'x' gm for each, no. of moles of each gas =
no. of moles of H₂ = x/2 = 0.5x moles
no.of moles of O₂ = x/32 = 0.031x moles
This shows that no. of moles of O₂ is very less so O₂ will become the limiting reagent.
Answer:
The product is Methyl cyanoacetate
Explanation: see structure attached
Answer:
2.6%
Explanation:
As, 1 ounce (oz) = 0.0625 pounds (lb)
Therefore, weight of baby at discharge = 7 lb,1 oz = 7+0.0625 lb = 7.0625 lb
Since, 1 oz = 0.0625 lb
⇒ 4 oz = 4×0.0625 = 0.25 lb
Therefore, weight of baby at birth = 7 lb,4 oz = 7+0.25 lb = 7.25 lb
The <u>amount of weight lost</u> is equal to the difference of weight of the baby at birth and discharge.
Therefore, <u>weight lost</u> = 7.25 lb - 7.0625 lb = <u>0.1875 lb</u>
Now, the <u>percentage of weight lost</u> by the baby is given by the amount of weight lost divided by the weight of the baby at birth.
Therefore, <u>the percentage of weight los</u>t = weight lost ÷ weight at birth = 0.1875 lb ÷ 7.25 lb × 100 = <u>2.6% </u>
Answer:
3.5hrs
Explanation:
Using the formula Speed = Distance/Time
Given
Speed = 8mi/hr
Distance = 28miles
Get the time
Time = Distance/Speed
Time = 28/8
Tme = 3.5hrs
Hence it will take 3.5hrs to travel
